1Consider the hash table below, using doublehashingNote: you can call h(x) as h1(x) and d(x) ash2(x)h(X) = X mod 11d(x) =( X mod 7) – (X mod 5)Double hashing function-------> Hash functionIf we want to insert 26, whereabouts it isplaced?0 1 2 34 5 6 78 9 1044907063No correct answer provided8

The answer to the above question is 8 table size = 11 key-value = 26 => x probe i = 1 formula to…

Consider the hash table below, using double hashing Note: you can call h(x) as h1(x) and d(x) as h2(x) h(X) = X mod 11 -------> Hash function d(x) =( X mod 7) – (X mod 5) Double hashing function If we want to insert 26, whereabouts it is placed? 1 2 3 4 5 6 7 8 9 10 44 90 70 63 No correct answer provided 8

Consider the hash table below, using double hashing Note: you can call h(x) as h1(x) and d(x) as h2(x) h(X) = X mod 11 -------> Hash function d(x) =( X mod 7) – (X mod 5) Double hashing function If we want to insert 26, whereabouts it is placed? 1 2 3 4 5 6 7 8 9 10 44 90 70 63 No correct answer provided 8

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Given values below: 66 47 87 900 126 140 145 500 177 285 393 395 467 566 620 735 Store the values into a hash table with ten buckets, each containing three slots. If a bucket is full, use the next (sequential) bucket that contains a free slot. And Store the values into a hash table that uses the hash function key % 10 to determine into which of ten chains (separate chaining) to put the value?
Create a hash table of size 8 using modular division method. Use hash function h(k) = 2k + 3 where k is the key value. Apply quadratic probing method in resolving collision. Insert the following keys in the hash table: 3, 2, 9, 6, 11, 13. Show the final hash table.
Please type your solution below for the question a. Suppose the hash tables in the two bridges B1 and B2 are empty.
Computer Science A hash function h defined h(k)=k mod 7, and linear probing is used to insert the keys 44, 45, 79, 55, 91, 18, 63 into a table indexed from 0 to 6. What will be the location of key 18?
T is an empty hash table. The size of T is 4 and the hash function is h(key) = key mod 4. Draw the hash table T after inserting the following item one by one: 24, 30, 29, 39, 30, 15, 14, 33.
Please type your solution below for the question. d. Suppose the hash tables in the two bridges B1 and B2 are all updated.
Insert the following sequence of keys in the hash table.Keys = {4, 2, 1, 3, 5, 6, 8}Use linear probing technique for collision resolution: h(k, i) = [h(k) + i] mod mHash function, h(k) = 3k + 1Table size, M = 10 Draw the hash table, compute the index where the hashvalue will be inserted for each key, and show how you would use the technique when a collisionoccurs.
Insert into a hash table with a maximum size of 10, the following keywords- apple, grape, orange, pineapple Hash function use Division . methodIf there is a collision handling with Linear Probing Create the final result hash table
Suppose you have a hash table HT and a hash function h, What does the following line mean? HT [ h(key) ] = key;
Double Hashing Given input {19, 29, 7, 116, 44, 8, 45}, a hash function h(x) = x mod 11 and the double hash h2(key) = 7 - (key mod 7). Show the resulting hash table using double hashing. copyAndPaste the table into the textBox for your nice answer. Please consider showing work for the h(x). [0] [1] [2] [3] [4] [5] [6] [7] [8] [9] [10]
A linear probing hash table of length 10 uses the hash function h(x) = x mod 10 + 1. mod is the reminder operator. For example the h(42) = 42 mod 10 + 1 = 2 + 1 = 3 so we insert 42 in the position 3 in the array. After inserting 6 integer keys into an initially empty hash table, the array of keys is…
The 9-entry hash table that results from using the hash function, h(i) = (2i+7) mod 9, to hash the keys 12, 5, 13, 4, 10, 19, 8, 3, and 28, assuming collisions are handled by linear probing as follows: 0 1 2 3 4 5 6 7 8 10 19 3 28 12 8 13 4 5 group answer choice a) True b) False