Consider the int Array below and determine the values of A and B so that Array[0] has an integer in the range Array[0] =A + rand () & B: O a.A = = -23, B = 95 O b.A = -24 , B 95 Oc.A = -22 , B = 94 Od.A = -23 B = 96 = -23 , Oe.A - - B = 94
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- Write a program to ask the user for the number of arrays he wants to maintain and then populate eacharray by taking elements from the user. Merge all these arrays in another array and finally remove duplicateelements from the merged array.given an array of integer values , return true if 6 appears as either the first or last element in the array. firstLast6([1,2,36]) true firstLast([6,1,2,3]) true firstLast([13,6,1,2,3]) falseAn array having a character subscript can be indexed using a computer language, as in CHR_ARRAY['A':'D']. In this scenario, the characters' ordinal numbers (ORDs), such as ORD('A') = 1, ORD('B') = 2, ORD('Z') = 26 and so on, are used to designate the array's elements, CHR_ARRAY['A'], CHR_ARRAY['B'], and so on. Beginning at position 500, two arrays called TEMP[1:5, -1:2] and CODE['A':'Z', 1:2] are now kept in the RAM. Furthermore, CODE outperforms TEMP in storage. Determine the locations of the following addresses: (i) TEMP[5, -1], (ii) CODE['N',2], and (iii) CODE['Z',1].
- Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example: Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {I need help with creating a Java program described below: Minesweeper.Write a program that reads three numbers, m, n, and p and produces an m-by-n Booleanarray where each element is occupied with probability p. In the minesweeper game, occupiedcells represent bombs and empty cells represent safe cells.Print out the array using an asterisk for bombs and a period for safe cells.Then, create an integer two-dimensional array with the number of neighboring bombs (above,below, left, right, or diagonal). * * . . . * * 1 0 0. . . . . 3 3 2 0 0 . * . . . 1 * 1 0 0Write your code so that you have as few special cases as possible to deal with, by using an(m+2)-by-(n+2) Boolean array.Write a program to Build a 100-element array with the integers 1 through 100 for which shellsort utilises as many comparisons as it can discover, using increments of 1 4 13 40.
- Write a program that first reads an integer for the array size, then reads numbers intothe array, and finally outputs how many numbers have values that are greater than theaverage. For practice reasons, try not to use the index notation of arrays (e.g. myarray[i])at all. Use pointers instead.Write a program that prints at least 10 characters of your name (last, first) in uppercase at the terminal. Use a n by m array (i.e., a two dimensional array, with n (=7) as size of the first dimension and m (=10) as the second dimension) to represent each oversize letter. C++, the name is "Krish"Write a Program to Construct an array of 100 elements containing the numbers 1 through 100 for which shellsort, with the increments 1 4 13 40, uses as large anumber of compares as you can find.
- Write the method sum2D() which accepts a two dimensional integer array and returns the sum of all the elements of the array.# the method take another circular array and returns a linear array containing the common elements between the two circular arrays. def intersection(self, c2): # To Do print("==========Test 10==========") lin_arr9 = [10, 20, 30, 40, 50, None, None, None] c10 = CircularArray(lin_arr9, 5, 5) c10.printFullLinear() # This should print: 40, 50, None, None, None, 10, 20, 30 lin_arr10 = [5, 40, 15, 25, 10, 20, 5, None, None, None, None, None] c11 = CircularArray(lin_arr10, 8, 7) c11.printFullLinear() # This should print: 10, 20, 5, None, None, None, None, None, 5, 40, 15, 25 output = c10.intersection(c11) print(output) # This should print: [10, 20, 40]Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example:(in java) Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {