Consider the intersection curve C in the first octant, between the surfaces S1: P = (1,1,1) z=1-2² y S₂: y = 2x. Let a point on C, as shown in the figure: 2=1-x² P 2x H x A tangent vector to curve C at P corresponds to: A) = (1,2,-1) B) = (1, 1,-1) C) = (1,2,-2) D) 7 = (1,1,-2) Y

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