Consider the length of the simple pendulum is 1 and the mass of the pendulum bob is m. Obtain the equation for the Lagrangian for the simple pendulum when its kinetic energy is ml and the potential energy is mgl(1-cose cos ø) . (A) ml d-mgl(1- cos ) (B) - ml o – mgl (1-cos ) 2 (C) mlo +mgl (1- cos ø) (D) - ml - 2mgl (1-cos o) Answer tivate
Consider the length of the simple pendulum is 1 and the mass of the pendulum bob is m. Obtain the equation for the Lagrangian for the simple pendulum when its kinetic energy is ml and the potential energy is mgl(1-cose cos ø) . (A) ml d-mgl(1- cos ) (B) - ml o – mgl (1-cos ) 2 (C) mlo +mgl (1- cos ø) (D) - ml - 2mgl (1-cos o) Answer tivate
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Transcribed Image Text:Consider the length of the simple pendulum is 1 and the mass of the pendulum bob is m.
Obtain the equation for the Lagrangian for the simple pendulum when its kinetic energy is
1
mlo and the potential energy is mgl(1–cos ø) .
m².
2.
1
(A) -– mgl (1- cos ø)
ml²ø² –
1.
(B) – ml o-mgl(1-coso)
2
1
(C)ml'o +mgl(1-cos o)
2.
1
(D) ml o-2mgl (1- cos o)
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