Consider the matrix 0 an 0 0 where aan aye 0. Show that A is invertible and find its inverse. Answer: a11

Elementary Linear Algebra (MindTap Course List)
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ISBN:9781305658004
Author:Ron Larson
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Chapter6: Linear Transformations
Section6.4: Transistion Matrices And Similarity
Problem 15E
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72ll
6
10 p r:.0
...
Lect04.pdf
L0 d e]
then p(A) = 0
27. Consider the matrix
...
a22
A=
0 0
where a1an
-a + 0. Show that A is invertible and find its inverse.
Answer:
a11
a22
1
...
28. Show that if a square matrix 4 satisfies A? - 34+1=a then A- = 31-A
29. (a) Show that a matrix with a row of zeros cannot have an inverse.
(b) Slow that a matrix with a column of zeros cannot have än inverse,
30. Assuming that all matrices are x / and invertible, solve for D.
ABC"DBA"C AR
31. Assuming that all matrices are x and invertible, solve for D.
Answer:
32. If A is a square matrix and a is a positive integer, is it true that (A")' = (A")? Justify your answer.
33. Simplify:
D-
Answer:
34. Simplify:
AD-
In Exercises 35-37, determine whether A is invertible, and if so, find the inverse. [Hint: Solve AX = / for X.
by equating corresponding entries on the two sides.]
[10 1]
A=110
1
35.
0 1 1
Answer:
PE / YI
[1 1
A=100
011
36.
0 0 1
1 10
-1 11
37.
A
Answer:
Transcribed Image Text:72ll 6 10 p r:.0 ... Lect04.pdf L0 d e] then p(A) = 0 27. Consider the matrix ... a22 A= 0 0 where a1an -a + 0. Show that A is invertible and find its inverse. Answer: a11 a22 1 ... 28. Show that if a square matrix 4 satisfies A? - 34+1=a then A- = 31-A 29. (a) Show that a matrix with a row of zeros cannot have an inverse. (b) Slow that a matrix with a column of zeros cannot have än inverse, 30. Assuming that all matrices are x / and invertible, solve for D. ABC"DBA"C AR 31. Assuming that all matrices are x and invertible, solve for D. Answer: 32. If A is a square matrix and a is a positive integer, is it true that (A")' = (A")? Justify your answer. 33. Simplify: D- Answer: 34. Simplify: AD- In Exercises 35-37, determine whether A is invertible, and if so, find the inverse. [Hint: Solve AX = / for X. by equating corresponding entries on the two sides.] [10 1] A=110 1 35. 0 1 1 Answer: PE / YI [1 1 A=100 011 36. 0 0 1 1 10 -1 11 37. A Answer:
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