Consider the nonlinear system of equations 22 – 3y = 4, 4x – y = 4. (2,-4), one step of Newton's method gives to %3D Starting from the initial approximation (x0,Y0) = decimal places

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 17EQ
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Consider the nonlinear system of equations
2² – 3y = 4,
4x - Y
= 4.
Starting from the initial approximation (0, 40) = (2, –4), one step of Newton's method gives to
decimal places
%3D
Y1 =
Transcribed Image Text:Consider the nonlinear system of equations 2² – 3y = 4, 4x - Y = 4. Starting from the initial approximation (0, 40) = (2, –4), one step of Newton's method gives to decimal places %3D Y1 =
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