Consider the right endpalnts approximation of the area of the reglan. Observe the reglon between the graph of the function f(x) = 2x + 6 and the x-axls over the Interval [0, 2] with four circumsaribed rectangles, which is shown below. 10 -as 10 13 20 23 The ight endpoints of the n Intervals are Ax() where /= 1 to Then substitute Ax = and n = 4 to find the left end polnts of four Intervals. Thus, the right end points of four Intervals are Ax() = 0, wherel = 1 to 4. That is, the four right end points of the Intervals are 1, and 2. Therefore, the four Intervals are given as follows.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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Consider the right endpoints approximation of the area of the reglan.
Observe the reglon between the graph of the function f(x) = 2x + 6 and the x-axis over the Interval [0, 2] with four circumscribed rectangles, which Is shown below.
1.0
13
20
23
The right endpolnts of the n Intervals are Ax() where /= 1 to
Then substitute Ax =
-and n = 4 to find the left end polnts of four Intervals.
Thus, the right end polnts of four Intervals are Ax() =
), wherel =1 to 4.
That Is, the four right end polnts of the Intervals are
1.
and 2
Therefore, the four Intervals are glven as follows.
Transcribed Image Text:Consider the right endpoints approximation of the area of the reglan. Observe the reglon between the graph of the function f(x) = 2x + 6 and the x-axis over the Interval [0, 2] with four circumscribed rectangles, which Is shown below. 1.0 13 20 23 The right endpolnts of the n Intervals are Ax() where /= 1 to Then substitute Ax = -and n = 4 to find the left end polnts of four Intervals. Thus, the right end polnts of four Intervals are Ax() = ), wherel =1 to 4. That Is, the four right end polnts of the Intervals are 1. and 2 Therefore, the four Intervals are glven as follows.
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