Consider the same scenario of the previous question but imagine that the first block hits another one with mass my-5 kg that isresting at the bottom. The two blocks stick together after the collision. Determine the maximum height with respect to thebottom of the bowl that the two blocks reach. Express your answer in cm.Note: if you could not do problem (1), call v the velocity of m1 before hitting m2 and express your results in terms of it. This way you canget most of the credit for this problem.m1m2 A block of mass m;=2.5 kg is released from rest in a smooth (frictionless) hemispherical bowl of radius R-0.5 m from a height Rwith respect to the bottom of the bowl, as shown in the figure. Determine the speed of the block when it reaches the bottom ofthe bowl. Express your answer in m/s.m1

Solution: 1. The block of mass m1 is initially at a height of R from the bottom of the bowl. Let us…

Consider the same scenario of the previous question but imagine that the first block hits another one with mass my-5 kg that is resting at the bottom. The two blocks stick together after the collision. Determine the maximum height with respect to the bottom of the bowl that the two blocks reach. Express your answer in cm. Note: if you could not do problem (1), call v the velocity of m; before hitting m2 and express your results in terms of it. This way you can get most of the credit for this problem. m1 R m2

Consider the same scenario of the previous question but imagine that the first block hits another one with mass my-5 kg that is resting at the bottom. The two blocks stick together after the collision. Determine the maximum height with respect to the bottom of the bowl that the two blocks reach. Express your answer in cm. Note: if you could not do problem (1), call v the velocity of m; before hitting m2 and express your results in terms of it. This way you can get most of the credit for this problem. m1 R m2