Consider the simplex tableau given below. X1 X2 S1 S2 P 1 2 1 3 3 1 32 - 7 - 2 1 (A) The pivot element is located in column 1 and row 1. (B) The entering variable is x1 (C) The exiting variable is s1 (D) Enter the values after one pivot operation in the tableau below. X1 X2 S1 S2 1 2 1 3 - 4 1 20 12 7 1
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- Consider the following intermediate tableau (not the Initial Simplex tableau): p x1 x2 s1 s2 rhs 0 0 1 1/2 -1/2 3/2 0 1 0 1/2 1/2 5/2 1 0 0 2 -1 7 a) Determine the pivot column and the pivot element, and perform all the row operations for the entire pivot column to obtain the next new tableau. Once you have the new tableau, look at the numbers you have in the objective row and enter each one as requested in each box below. Note: Where applicable, fractions must be entered as 2/5, -1/3, and so on. Under column x1 in the objective row, you have: Under column x2 in the objective row, you have: Under column s1 in the objective row, you have: Under column s2 in the objective row, you have: Under column RHS in the objective row, you have: b) Given the new tableau that you obtained above, three interpretations are possible. In the box below, type or copy and paste whichever answer shown in boldface letters below that you think…a.) Formulate a LP model of this problem b.) Used revised simplex method to solve this problemFind the optimal solution for the following model using simplex
- What makes the simplex method so efficient?3. Solve the LP problem using the dual simplex method. (Please follow the example structure below) minimize x1 + 45x2+ 3x3 subject to: x1 + 5x2 - x3 >= 4 x1 + x2 + 2x3 >= 2 -x1 + 3x2 + 3x3 >= 5 -3x1 + 8x2 - 5x3 >= 3 Х1, X2, X3 ≥ 0. Consider the simplex tableau given below. (A) Where is the pivot element is located? (B) What is the entering variable (C) What is the exiting variable (D) Show the values after one pivot operation in the tableau
- Use the non-standard simplex method to solve. Show work by setting up the initial simplex tableau (with the columns labeled), circling the first pivot element, and giving the final simplex tableau. If there is no solution, then state which type: Not Feasible or Unbounded. If the solution is unique, then provide the solution with context. If there are infinite solutions, then describe the line segment containing the solutions by providing the two end points. Maximize: P=0.15x+0.17y subject to: 1.10x+1.30y<=5400 x+y>=5000 x>=0, y>=0Consider the following LP:Maximize z = 16x1 + 15x2subject to40x1 + 31x2 <=124-x1 + x2<= 1x1<=3x1, x2 >= 0(a) Solve the problem by the simplex method, where the entering variable is thenonbasic variable with the most negative z-row coefficient.Consider the simplex tableau given below. a. Show the values after one pivot operation in the tableau
- Determine the solutions of the LP model below using simplex method. Complete Tableaus 1 and 2 below by supplying the values for the items in red. Maximize: P=15x1 + 13x2 Subjec to: x1 ≤ 300 (place in R11) 2x1 + 3x2 ≤ 360 (place in R21) 3x1 + 5x2 ≤ 270 (place in R31) x1 ≥ 0, x2 ≥ 0With reference to the solution of LPP simplex method table . Max z = x1 + x2 s.t. 2x1 + x2 ≤ 20 x1 +3x2 ≤ 15 x2 ≤ 4 x1, x2 ≥ 0Therefore, the solution from the simplex tableau is as shown below. x1 =_____ x2=_____ x3=______ S1=______ s2=______ z=______