Consider the surface S: z = 4ex^2  - 4xy, where P (0, 1, 1) is a point on S. An equation of the tangent line to S at P, in the direction of the vector v = (−2, −4) corresponds to: Answers in the picture:

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter1: Vectors
Section1.2: Length And Angle: The Dot Product
Problem 70EQ
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Consider the surface S: z = 4ex^2  - 4xy, where P (0, 1, 1) is a point on S. An equation of the tangent line to S at P, in the direction of the vector v = (−2, −4) corresponds to:

Answers in the picture:

А) (г, у, 2) — (0, 1, 1) + t(-2, —4, 8). t € R
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В) (г, у, 2) — (0, 1, 1) + t(-2, —4, 6), t € R
С) (л, у, 2) — (0, 1, 1) + t(-2, —4, -6). t€ R
D) (г, у, 2) — (0, 1, 1) + t(-2, —4, -8), t € R
Transcribed Image Text:А) (г, у, 2) — (0, 1, 1) + t(-2, —4, 8). t € R | В) (г, у, 2) — (0, 1, 1) + t(-2, —4, 6), t € R С) (л, у, 2) — (0, 1, 1) + t(-2, —4, -6). t€ R D) (г, у, 2) — (0, 1, 1) + t(-2, —4, -8), t € R
S: z = 4e" – 4xy,
Transcribed Image Text:S: z = 4e" – 4xy,
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