Consider the system described by the following second-order differential equation. dy(t) dt d²y(t) dt² — 6y(t) = x(t) Suppose that the following input signal x(t) was fed into the system. Suppose further that at t = 0, y(t) = 4 and y' (t) = 0.5. + t>0 x(t) = {4€ ²,20} t<0 The solution of the forced response is Yp(t) = Ce-2t, where C = The solution of the total response is y(t) = K₁e³¹t + K₂e³2t + Ce-2¹, where K1 = and K2 = Note: Assume K₁ ≤ K₂

Consider the system described by the following second-order differential equation. dy(t) dt d²y(t) dt² — 6y(t) = x(t) Suppose that the following input signal x(t) was fed into the system. Suppose further that at t = 0, y(t) = 4 and y' (t) = 0.5. + t>0 x(t) = {4€ ²,20} t<0 The solution of the forced response is Yp(t) = Ce-2t, where C = The solution of the total response is y(t) = K₁e³¹t + K₂e³2t + Ce-2¹, where K1 = and K2 = Note: Assume K₁ ≤ K₂

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.16P

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