Consider the vectors 7₁ = €₂ = T3 = 1 in R4. Use the Gram-Schmidt process to find an orthogonal basis for the subspace span{1, 72, 73}.

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter5: Inner Product Spaces
Section5.3: Orthonormal Bases:gram-schmidt Process
Problem 41E: Use the inner product u,v=2u1v1+u2v2 in R2 and Gram-Schmidt orthonormalization process to transform...
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Note first that the vectors 71, 72, and 73 are linearly independent (a necessary precondition for performing
the Gram-Schmidt process); you can check this by row-reducing the coefficient matrix [₁
confirming that all three columns have pivots. Gram-Schmidt then produces the orthogonal basis
2 3] and
1/2
-2/3
{V1, U2, U3} =
2/3
181
2/3
0
If you like, you can scale the second and third vectors to clear fractions (the result will still be an orthogonal
basis).
Transcribed Image Text:Answer Note first that the vectors 71, 72, and 73 are linearly independent (a necessary precondition for performing the Gram-Schmidt process); you can check this by row-reducing the coefficient matrix [₁ confirming that all three columns have pivots. Gram-Schmidt then produces the orthogonal basis 2 3] and 1/2 -2/3 {V1, U2, U3} = 2/3 181 2/3 0 If you like, you can scale the second and third vectors to clear fractions (the result will still be an orthogonal basis).
Consider the vectors
€₁ =
₂ =
3: = 1
in R4. Use the Gram-Schmidt process to find an orthogonal basis for the subspace span{1, 72, 73}.
Transcribed Image Text:Consider the vectors €₁ = ₂ = 3: = 1 in R4. Use the Gram-Schmidt process to find an orthogonal basis for the subspace span{1, 72, 73}.
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