Consider two identical, finite, isolated systems of constant heat capacity C at temperatures T, and T2 (T> T:). An engine works between them until their temperatures become equal. Taking into account that the work performed by the engine will be maximum (= Wmax) if the process is reversible (equivalently, the entropy change of the entire system is zero). the value of Wmax is: Q.17 (A) C(T, - T2) (B) C (T – T2)/2 (C) C(T, + T2 - T;T2) 2 (D) C(/T, - VT2)
Consider two identical, finite, isolated systems of constant heat capacity C at temperatures T, and T2 (T> T:). An engine works between them until their temperatures become equal. Taking into account that the work performed by the engine will be maximum (= Wmax) if the process is reversible (equivalently, the entropy change of the entire system is zero). the value of Wmax is: Q.17 (A) C(T, - T2) (B) C (T – T2)/2 (C) C(T, + T2 - T;T2) 2 (D) C(/T, - VT2)
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![Q.17 Consider two identical, finite, isolated systems of constant heat capacity C at temperatures T, and
T2 (T> T:). An engine works between them until their temperatures become equal. Taking into
account that the work performed by the engine will be maximum (= Wmax) if the process is
reversible (equivalently, the entropy change of the entire system is zero), the value of Wmax is:
(A) C(T, – T2)
(B) C (T, – T2)/2
(C) C(T, + T2 -- T;T2)
(D) C(/T,
- T)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa19a2886-df78-43e6-912d-2069c7bc6f40%2Fda7eb184-d9ff-40cd-a3e7-bc406d670264%2Ft4ezs1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q.17 Consider two identical, finite, isolated systems of constant heat capacity C at temperatures T, and
T2 (T> T:). An engine works between them until their temperatures become equal. Taking into
account that the work performed by the engine will be maximum (= Wmax) if the process is
reversible (equivalently, the entropy change of the entire system is zero), the value of Wmax is:
(A) C(T, – T2)
(B) C (T, – T2)/2
(C) C(T, + T2 -- T;T2)
(D) C(/T,
- T)
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