Consider what happens when the CPU performs a load operationsuch as movq A,%rax
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Consider what happens when the CPU performs a load operation
such as
movq A,%rax
Step by step
Solved in 2 steps
- How can we stop a CPU from wasting time executing several instructions at once? Is this method feasible without certain resources? Show their typical production.If random access memory (RAM) and cache memory (both of which are comprised of transistors), then what is the function of cache memory? Do we need several different forms of memory, or can we get by with only one?What is the minimum number of cycles needed to completely execute n instructions on a CPU with a k stage pipeline? Find a formula.
- Consider the following processes with the given CPU arrival time and burst time. Please use the round-robin with quantum 10 to compute for the waiting times for each process.The inquiry is phrased as follows: "Are you able to offer an overview of CPU scheduling strategies?"olu CPU has the following instruction performance. What is the average CPI?
- Solve the 8085 Write a program to load twenty memory locations starting from 8005H, where each location's content should increases by 2 over the previous one, however, the first location should contain 04H, assuming that the programs start at memory location 9009H?Consider the following processes with the given CPU arrival time and burst time. Please use the shortest remaining time first algorithm to make a Gantt chart.Consider the following processes with the given CPU arrival time and burst time. Please use the round-robin with quantum 10 to make a Gantt chart.
- Modiflow y the beprogram given to include response time program;FCFS CPU SCHEDULING ALGORITHM #include<stdio.h>#include<conio.h>main(){int bt[20], wt[20], tat[20], i, n; float wtavg, tatavg;clrscr();printf("\nEnter the number of processes -- "); scanf("%d", &n); for(i=0;i<n;i++){printf("\nEnter Burst Time for Process %d -- ", i); scanf("%d", &bt[i]);}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0]; for(i=1;i<n;i++){wt[i] = wt[i-1] +bt[i-1];tat[i] = tat[i-1] +bt[i]; wtavg = wtavg + wt[i]; tatavg = tatavg + tat[i];}printf("\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n");for(i=0;i<n;i++){printf("\n\t P%d \t\t %d \t\t %d \t\t %d", i, bt[i], wt[i], tat[i]);}printf("\nAverage Waiting Time -- %f", wtavg/n);printf("\nAverage Turnaround Time -- %f", tatavg/n); getch();}Modiflow y the beprogram given to include response time program;FCFS CPU SCHEDULING ALGORITHM #include<stdio.h>#include<conio.h>main(){int bt[20], wt[20], tat[20], i, n; float wtavg, tatavg;clrscr();printf("\nEnter the number of processes -- "); scanf("%d", &n);for(i=0;i<n;i++){printf("\nEnter Burst Time for Process %d -- ", i); scanf("%d", &bt[i]);}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0];for(i=1;i<n;i++){wt[i] = wt[i-1] +bt[i-1];tat[i] = tat[i-1] +bt[i]; wtavg = wtavg + wt[i]; tatavg = tatavg + tat[i];}printf("\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n");for(i=0;i<n;i++){printf("\n\t P%d \t\t %d \t\t %d \t\t %d", i, bt[i], wt[i], tat[i]);}printf("\nAverage Waiting Time -- %f", wtavg/n);printf("\nAverage Turnaround Time -- %f", tatavg/n); getch();}On modern computers, we need to use parallel execution to be able to use their processors effectively. However, parallel execution is not trivial. For the following programs, identify whether they are parallelizable. Simply answer with yes or no.