Construct a Java RE that describes the set of strings that are legal REs over the binary alphabet, but with no occurrence of parentheses within parentheses. For example, (0.*1)* or (1.*0)* is in this language, but (1(0 or 1)1)* is not.
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Construct a Java RE that describes the set of strings that are
legal REs over the binary alphabet, but with no occurrence of parentheses within parentheses. For example, (0.*1)* or (1.*0)* is in this language, but (1(0 or 1)1)*
is not.
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- Write a Java program to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string. Provide an explanation of the code and its time and space complexity.Write a Java program to find the longest common prefix among a given array of strings. If there is no common prefix, return an empty string "".Print all permutation of string in JAVA with repeat also
- Build a TM over the alphabet Σ = {a,b} that accepts the language where each word has twice asmany b’s as a’s.Write a CFG to generate the language of all strings that have more a's than b's (not necessarily only one more, as with the nonterminal A for the language EQUAL, but any number more a's than b's). {a aa aab aba baa aaaa aaab ... }Consider the language of all strings which contain two consecutive 0 that ? = {11, 111, 110, 011, 1111, 1110, 1101, 1100, 1011, 0111, 0110, 0011, … }. Give a RE corresponding to this language.
- Implement the following function in C programming language that get a string, and compute an array of non-empty tokens of the string containing only lower-case letters. For example: ● For a string "abc EFaG hi", the list of tokens with only lower-case letters is ["abc", "hi"]. ● For a string "ab 12 ef hi ", the list of such tokens is ["ab","ef","hi"]. ● For a string "abc 12EFG hi ", the list of such tokens is ["ab","hi"]. ● For a string " abc ", the list of such tokens is ["abc"]. ● For a string "+*abc!! B" the list of such tokens is empty.That is, we break the string using the spaces as delimiters (ascii value 32), and look only at the tokens with lower-case letters only . The function get_tokens gets a string str, and returns the array with the tokens containing only lower-case letters in the correct order. The length of the array should be the number of tokens, computed in count_tokens. char** get_tokens(const char* str); For example:● get_tokens("abcEFaG…Create a DFA that recognizes the language of strings over the alphabet Σ = {a, b} that consist exactly of an even number of a's followed by 0 or more b's, where the number of b's is a multiple of 3.Implement the following two functions that allow breaking a string into non-empty tokens using a given delimiter in c language . For example, ● For a string “abc-EFG-hi”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc-EFG---hi-”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc”, and a delimiter ‘ ’ : the list of tokens is [“abc”] ● For a string “++abc++”, and a delimiter ‘+’ : the list of tokens is [“abc”] That is, we break the string using the given delimiter, and the tokens are only the non-empty substrings. The function count_tokens gets a string str, and a char delim, and returns the number of tokens in the string separated by delim. int count_tokens(const char* str, char delim); For example● count_tokens("abc-EFG--",'-')needstoreturn2. ● count_tokens("++a+b+c",'+')needstoreturn3.● count_tokens("***",'*')needstoreturn0.The function get_tokens gets a string str, and a char delim, and returns the…
- Implement the following two functions that allow breaking a string into non-empty tokens using a given delimiter in c language . For example, ● For a string “abc-EFG-hi”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc-EFG---hi-”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc”, and a delimiter ‘ ’ : the list of tokens is [“abc”] ● For a string “++abc++”, and a delimiter ‘+’ : the list of tokens is [“abc”] That is, we break the string using the given delimiter, and the tokens are only the non-empty substrings.write a program in C++ Fibonacci NumbersThe Fibonacci numbers are defined by the sequencef1 = 1f2 = 1fn = fn-1 + fn-2Reformulate that as5t1 = 1;t2 = 1;nextTerm = t1 + t2;After that, discard t1, which is no longer needed, and set t1 to t2 and t2 to nextTerm.Repeat fnew an appropriate number of times. Implement a program that given a numberN, prints the first N numbers in the Fibonacci sequence. For example, given the number8, the output isThe Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21In C language, implement the following two functions that allow breaking a string into non-empty tokens using a given delimiter. For example, For a string "abc-EFG-hi", and a delimiter '-': the list of tokens is ["abc", "EFG", "hi"] For a string "abc-EFG---hi-", and a delimiter '-': the list of tokens is ["abc", "EFG", "hi"] For a string "abc", and a delimiter ' ': the list of tokens is ["abc"] For a string "++abc++", and a delimiter '+': the list of tokens is ["abc"] That is, we break the string using the given delimiter, and the tokens are only the non-empty substrings. 1. The function count_tokens gets a string str, and a char delim, and returns the number of tokens in the string separated by delim. int count_tokens(const char* str, char delim); For example count_tokens("abc-EFG--", '-') needs to return 2. count_tokens("++a+b+c", '+') needs to return 3. count_tokens("***", '*') needs to return 0. 2. The function get_tokens gets a string str, and a char delim, and returns the…