Construct a plot on normal probability paper   Measurement results of the diameter of a shaft turned on a CNC lathe Specifications: 0.7495 – 0.7505     1 2 3 4 5 6 7 8 9 10 1 0.7501 0.7501 0.7503 0.7501 0.7502 0.7497 0.7497 0.7500 0.7502 0.7496 2 0.7501 0.7500 0.7498 0.7502 0.7496 0.7504 0.7501 0.7502 0.7502 0.7501 3 0.7500 0.7499 0.7502 0.7503 0.7500 0.7503 0.7503 0.7500 0.7500 0.7499 4 0.7500 0.7502 0.7503 0.7501 0.7498 0.7500 0.7502 0.7503 0.7498 0.7501 5 0.7501 0.7499 0.7501 0.7501 0.7499 0.7500 0.7498 0.7501 0.7501 0.7500   Draw vertical lines on the graph to represent the LSL and USL. Draw horizontal lines to represent three standard deviations.   Estimate of % nonconforming above USL = Estimate of % nonconforming below LSL = Total estimated % nonconforming beyond the specification limits =

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Construct a plot on normal probability paper
 
Measurement results of the diameter of a shaft turned on a CNC lathe
Specifications: 0.7495 – 0.7505
 
 
1
2
3
4
5
6
7
8
9
10
1
0.7501
0.7501
0.7503
0.7501
0.7502
0.7497
0.7497
0.7500
0.7502
0.7496
2
0.7501
0.7500
0.7498
0.7502
0.7496
0.7504
0.7501
0.7502
0.7502
0.7501
3
0.7500
0.7499
0.7502
0.7503
0.7500
0.7503
0.7503
0.7500
0.7500
0.7499
4
0.7500
0.7502
0.7503
0.7501
0.7498
0.7500
0.7502
0.7503
0.7498
0.7501
5
0.7501
0.7499
0.7501
0.7501
0.7499
0.7500
0.7498
0.7501
0.7501
0.7500
 
Draw vertical lines on the graph to represent the LSL and USL.
Draw horizontal lines to represent three standard deviations.
 
Estimate of % nonconforming above USL =
Estimate of % nonconforming below LSL =
Total estimated % nonconforming beyond the specification limits =
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