Continuity and differentiability are important conditions in many theorems in Calculus. One such important theorem is called the Mean Value Theorem. It tells us, under certain conditions, that there is a location where the instantaneous rate of change will equal the average rate of change. b-a If f(x) is continuous on [a, b] and differentiable on (a, b), then there exists a number c, with a < c < b such that f'(c) = f(b) = f(a). Determine which functions appear to satisfy the conditions of the Mean Value Theorem on the given interval. (i) f(x) = |x-5| (ii) x² x+6 g(x) = پر h(x) 10 x on the interval 4 ≤ x ≤ 11 on the interval -5 ≤ x ≤ 6 on the interval 0 ≤ x ≤ 10 ---Select--- ---Select--- ---Select---

Algebra and Trigonometry (MindTap Course List)
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Chapter2: Functions
Section2.5: Linear Functions And Models
Problem 51E
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Continuity and differentiability are important conditions in many theorems in Calculus. One such important theorem is called the Mean Value Theorem.
It tells us, under certain conditions, that there is a location where the instantaneous rate of change will equal the average rate of change.
If f(x) is continuous on [a, b] and differentiable on (a, b), then there exists a number c, with a < c < b such that f'(c)
Determine which functions appear to satisfy the conditions of the Mean Value Theorem on the given interval.
(i) f(x) = |x-5|
x²
(ii)
x+6
(iii)
g(x):
=
h(x)
f
10
X
on the interval 4 ≤ x ≤ 11
on the interval -5 ≤ x ≤ 6
on the interval 0 ≤ x ≤ 10
---Select---
--Select---
---Select---
=
f(b) – f(a).
b-a
Transcribed Image Text:Continuity and differentiability are important conditions in many theorems in Calculus. One such important theorem is called the Mean Value Theorem. It tells us, under certain conditions, that there is a location where the instantaneous rate of change will equal the average rate of change. If f(x) is continuous on [a, b] and differentiable on (a, b), then there exists a number c, with a < c < b such that f'(c) Determine which functions appear to satisfy the conditions of the Mean Value Theorem on the given interval. (i) f(x) = |x-5| x² (ii) x+6 (iii) g(x): = h(x) f 10 X on the interval 4 ≤ x ≤ 11 on the interval -5 ≤ x ≤ 6 on the interval 0 ≤ x ≤ 10 ---Select--- --Select--- ---Select--- = f(b) – f(a). b-a
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