Convert the following expressions from infix to reverse Polish (postfix) notation. Please don't put any space when entering. (6*3) / 2+5
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- with the given expression where a = 5, b = 6, d = 8, e = 2, f = 4, g = 6, h = 4, j = 4, x = 2, y=2 Write the infix, prefix, postfix notationsConvert the following infix expressions to postfix. (3+1) * ((1+2) * (5+4)) please write step-by-step on paperConvert the following expression from reverse Polish notation to infix notation.Q.) U V W X Y Z + × + × +
- Convert the following expression from infix to reverse Polish (postfix) notation.Q.) W × X + W × (U × V + Z )Convert the following expression from infix to reverse Polish (postfix) notation.Q.) (8 − 6)/2Q1 \ Convert the following infix expression into postfix one: (A+B^D)/(D-F)+G PS: you have to illustrate the different steps of this conversion one by one.
- . Convert the following expression from reverse Polish notation to infix notation.Q.) 5 2 + 2 × 1 + 2 ×Convert the following infix expression into postfix notation. (A*B+(C/D))-F (A+B)*C/ A*B+(C/D) Evaluate following prefix expressions /-AB*+DEF *^+A/BD-EFG /*-AB/DE**FGH Where, A=1, B=2, C=3, D=4, E=2, F=2, G=4, H=3Convert the following infix expression into its equivalent postfix expression: (i) (a + b) * c (ii) (a + b) * (c + d) (iii) 95 + 36 * + 97 - 1 (iv) 6 + 9 =