Correct this code so that the verifier for this number "25431" is valid and presents 5 examples in which it must be valid and 5 examples for which it must be invalid, requirements: they must not have an extension greater than 5 digits. The pairs are added, the odd ones are multiplied without counting the intimate digit, then both results are added and finally it is divided by 10 if the residue is equal to the last digit then it will be valid: class CheckDigit: def __init__(self, account_code): self.account_code = account_code def is_valid(self): veriDigRes = 0 # returned 0 if size of account_code is less than 4 if len(self.account_code) < 4: return 0 for i in range(0, len(self.account_code)): #summing digits of even position if i%2 == 0: veriDigRes += int(self.account_code[i]) # taking product of odd positions else: veriDigRes *= int(self.account_code[i]) # taking residue of the division is extracted for 10 veriDig = veriDigRes % 10 if(veriDig == int(self.account_code[-1])): return 1 return 0 if __name__ == "__main__": account_code = input("Enter account code: ") check_digit = CheckDigit(account_code) if check_digit.is_valid() == 1: print("account_code is valid") else: print("account_code is invalid")
Correct this code so that the verifier for this number "25431" is valid and presents 5 examples in which it must be valid and 5 examples for which it must be invalid, requirements: they must not have an extension greater than 5 digits. The pairs are added, the odd ones are multiplied without counting the intimate digit, then both results are added and finally it is divided by 10 if the residue is equal to the last digit then it will be valid: class CheckDigit: def __init__(self, account_code): self.account_code = account_code def is_valid(self): veriDigRes = 0 # returned 0 if size of account_code is less than 4 if len(self.account_code) < 4: return 0 for i in range(0, len(self.account_code)): #summing digits of even position if i%2 == 0: veriDigRes += int(self.account_code[i]) # taking product of odd positions else: veriDigRes *= int(self.account_code[i]) # taking residue of the division is extracted for 10 veriDig = veriDigRes % 10 if(veriDig == int(self.account_code[-1])): return 1 return 0 if __name__ == "__main__": account_code = input("Enter account code: ") check_digit = CheckDigit(account_code) if check_digit.is_valid() == 1: print("account_code is valid") else: print("account_code is invalid")
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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The easiest way to think of a constructor in object-oriented programming (OOP) languages is:
Question
Correct this code so that the verifier for this number "25431" is valid and presents 5 examples in which it must be valid and 5 examples for which it must be invalid, requirements: they must not have an extension greater than 5 digits. The pairs are added, the odd ones are multiplied without counting the intimate digit, then both results are added and finally it is divided by 10 if the residue is equal to the last digit then it will be valid:
class CheckDigit:
def __init__(self, account_code):
self.account_code = account_code
def is_valid(self):
veriDigRes = 0
# returned 0 if size of account_code is less than 4
if len(self.account_code) < 4:
return 0
for i in range(0, len(self.account_code)):
#summing digits of even position
if i%2 == 0:
veriDigRes += int(self.account_code[i])
# taking product of odd positions
else:
veriDigRes *= int(self.account_code[i])
# taking residue of the division is extracted for 10
veriDig = veriDigRes % 10
if(veriDig == int(self.account_code[-1])):
return 1
return 0
if __name__ == "__main__":
account_code = input("Enter account code: ")
check_digit = CheckDigit(account_code)
if check_digit.is_valid() == 1:
print("account_code is valid")
else:
print("account_code is invalid")
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