- (cos:) 1. cos (tan) 2. csc -1 (tan) 3. tan n-1

Q: 1 in tan 3 +coS -1

A:

Q: tan3x)dx tan Evaluate: cos23x A - In|sec (tan3x)|+C - In|cos (tan3x)| +C B © In cos(tan3x)| +C in…

A:

Q: 15) tan-l –1 --1 V2 17) cos 2 1 19) tan- 1

A: Given: 16)  tan-1-1

Q: tan(tan3x)dx Evaluate: cos-3x -In |sec (tan3x)| + C (B ® - in [cos(tan3x)| + C © - sin( tan3x)| + c…

A: We need to evaluate the following integral I = ∫tantan3xcos23xdx…

Q: tan x sec X 3 10 cos xdydx

A: Given : Double integral ∫0π/2∫0tan x sec x y3 cos10x dydx   To find : Evaluate the given double…

Q: If tan x = -1/3, cos x > 0,, then | sin 2x -6 cos 2x -1 tan 2x -3/4

A:

Q: 1 sec- x = cos

A: Given, sec-1x=cos-11x   Check it is True or False:

Q: (3sin(0.3)) + cos(tan-(4.9))

A: put calculator in radian mode. 0.88656+0.19996=1.086 ans :d

Q: 2 (tan²x + 1)√sin2x.dx= (tan², 0

A: Find your answer below

Q: Establish each identity.

A: given,

Q: 2-sec2x: COS2X = COS X

A: Given query is to verify the identity

Q: tan (0) +1 1) sec(e) = sec(0) cos(@) +1 2) tan (0) cos(@) sec(@)-1

A: See the details solution in below

Q: tan(e) cos(0) - sec(0)

A:

Q: If tan x = 3, cos x > 0, , then - sin 2x cos 2x tan 2x %3D

A:

Q: arctan[2 cos(³)] is equal to: COS

A: Given that the expression arctan2cos32. Find the value of arctan2cos32.

Q: value of cos x is given. Find sin x and 3T xET, 15 X= 17'

A:

Q: if Sec X = 2 then tanx +Cos X =

A:

Q: - y = sin² (-1) y = cos" - y = arctan 0

A: This question is based on general solution of  Trignometric function.

Q: cos O sec 0 48. cos? wwww. www + tan? 0

A: We have to simply the given expression.

Q: How can I rewrite: sin(cos^-1(x)*cos(tan^-1(y)-cos(cos^-1(x))*sin(tan^-1(y))  as an algebraic…

A: Given expression

Q: 3. sin[cos¯(4/5) – tan-'(3/4)]

A:

Q: If tan a = - 1 then tan( – x) = If sin æ = 0.4 then sin( – æ) = If cos z = 0.5 then cos( – 2)= If…

A:

Q: 1-Cos 2x 1+ Cos 2x ix) tan x=

A: Prove :

Q: Simplify cos-1(cos(x)) if 0 ≤ x ≤ ?. cos-1(cos(x))=

A:

Q: sin2x -dp- cos x+cos*x-2cos?x

A:

Q: ( tan( tan3x)dx Evaluate: cos²3x A -In |sec(tan3x)| + C 3 |cos(tan3x)|+C B © --n |sin(tan3x)|+c O…

A: Evaluate: I=∫tantan 3xcos2 3xdx

Q: sec : tan/ sin :: cos :

A: As we know cos and sec are reciprocal of each other.  Therefore sec:tan/sin Then cos:sin/tan

Q: 1-cos?x 4. tanx sinxcosx

A:

Q: cos/ 3 17 cos (TA +x) tanx

A:

Q: 1. If tan a = - 3.5 then tan( – 2) = 2. If sin æ = 0.4 then sin( – æ) = 3. If cos x = 0.9 then cos(…

A: 1.  tan is negative in 4th quadrant tan(-x)=-tanx= 3.5 2. sin is negative in 4th quadrant…

Q: 9. cos(x-)

A:

Q: 1. cos t (1 + tan²t) sin ß sec ß + cos ß csc ß 2.

A: Given : 1. cost1+tan2t2. sinβsecβ+cosβcscβ

Q: cos 2x+1 = 1+ tan?x 2 cos4x

A:

Q: 1 1. sec-1 x = cos-1 = cos

A: we have to show that the given relation.

Q: Determine the exact value of csc ( cos-1) – cos (tan-) COs-1 COS 8. |

A: find the exact value in the following way:-

Q: If cos x = 2/3 Find sin x and tan 2x

A: To find: The value of sin x and tan 2x. Given: The value of cos x is 23. Concept used: Trigonometric…

Q: Find x where 0 ≤ x ≤ 2π. cos x - tan²x = 1

A:

Q: What is tan x if csc x = -V34/3 and cos x < O? * V34 CSC X =

A: Given, cscx=-343 sinx=1cscx=-334 we know, sin2x+cos2x=1 934+cos2x=1cosx=2534=-534

Q: Find cos x if tan x= -(2 √2)/2 and sin x= √6/3

A:

Q: If tan(x+y) tan(x-y) = 1 then find the value of tanx

A: From the given data:

Q: If tan x = -1/3, cos x > 0,, then sin 2x = ; cos 2x = tan 2x =

A:

Q: TI tant@-2 tan Bzl show that 2cose - Cos"B2o

A:

Q: 25n - If cos-1 '(cos = y , Find value of y?

A: For a∈ℝ cos-1(cos a)=a                 (1) Given equation is: cos-1cos25π6=y           (2) Compare…

Q: sec(x)cos(3x)=0 from [-pi/2, pi,2]

A: sec x cos 3x=0          [-π/2,π/2] sec x (4 cos3x - 3 cos x) = 0 [cos 3x= 4 cos3x - 3 cos x] 4 sec x…

Q: given tanx= -3/4 and 0*<x<180* , find the exact value of cos(x/2)

A: To solve the following problem

Q: Verify: cos x+4 cos x+4 2 sec x+1 %D cos x+2 sec x

A: Given,  cos2x+4cosx+4cosx+2= 2secx+1secx  We have to verify relationship.

Q: 2x,given  tanx=2 and cosx>0

A:

Q: tan x- cotx + 2 cos? x = 1 tan x + cotx

A: tanθ =sinθcosθ cotθ=cosθsinθ sin2θ+cos2θ=1