cos 5x Find lim ( x³ + 10,000 x→0

Q: e* – 1 lim V1+x -1 x→0

A:

Q: 8. (x - 1) dx √x lim

A:

Q: sin 04) find limx-2n 2x-4n S0 (x²+x+1)* Q5) lim- (r²+1)100

A: In the given question we have to find the limit of the question 4 and question 5. the question 4 is…

Q: X x+cos (-3x) 16) lim

A: To find the limit  limx→-∞xcos-3x

Q: 2) lim (x – T)tan5

A:

Q: xe 1. lim, »o X→0 1-e*

A:

Q: 1 Evaluate the lim sin x>0

A:

Q: Evaluate

A: To evaluate limx→0 e2x-1xSubstituting x=0 , 00 form is obtained Hence , L' Hospital's rule can be…

Q: sin(1 – t) |2 – 2t| (b) [8 marks] lim t+1-

A: this is left hand limit then limit approaches from left side

Q: lim (cos(9x)) (+) x-0+

A:

Q: x csc (2x) lim cos (5x x->0

A:

Q: -2x lim (e cOs x) х) x → 00

A:

Q: X (b) lim 0 DO (c) lim xln 1

A: (b). Given: limx→0+lnxx

Q: 3* Evaluate (a) lim sin y and (b) lim y x-1 Vx +5

A: we have to evaluate the following: a)  limy→π3 siny b) limx→-13xx+5

Q: • If y = cos x2 + x² then y(4) = 8x? sin x² + 0 TO FO x-5 • lim х-5 х2-25 = 10 FO

A:

Q: (a) lim sih 7x (b) lim x 0 sin 7x x - 9 (c) lim x-9 x - 3

A:

Q: x arcsin(kx) lim sin((k – 1)x)(e2- – 1) ||

A:

Q: tan2x 4) lim, -X, 2 x- 2

A: Explanation of the answer is as follows

Q: 44. lim sin² x x→n/4

A:

Q: Find lim. Sin (X/y X-T/4

A:

Q: (a) lim 1-cos() 3x (b) lim xe 1/x (Hint: xe

A:

Q: tan( xy) lim (х.у) >(0.1) х"у+x = ? 1 (b) 2 1 (c) 3 (a) 0 (e) 1

A:

Q: Q:B/ Find lim, [tan x-sec x].

A:

Q: 1 + cos(x) a) lim %3D 20 -x ) lim x-1( In(61x-60)

A: Given, limx->π (1+ cos (x))/(6(x-π)²) = (1/6)limx->π (1+ cos (x))/((x-π)²) = (1/6)limx->π…

Q: (1 – V3x lim tan- 3 + x x-00

A:

Q: 4x(1 — сos(x)) lim х — sin(x) х>0

A: Because the limit is in 0/0 form. Apply L'hopital's rule.

Q: 3* Evaluate (a) lim sin y and (b) lim x→-I /x + 5

A: To evaluate: a) limy→π3 sin y b) limx→-1 3xx+5

Q: 2 lim(cosx)x² =? x→0

A: Given: limx→0cosx2x2=limx→0cos2x2x

Q: 15x 5. Find lim using special limits. X→0 sin 3x

A:

Q: (d) lim (e) lim (1 – sin(x))/-

A:

Q: xsinx lim x→0 e*+e¯x-2cosx

A: Since, we have been given up the expression:-limx→0 x sin (x)ex+e-x-2 cos (x)-(i)Since,on applying…

Q: tan nx 3) lim x→0

A:

Q: Q5:The value of: * sin (5x) lim I-0

A: We have to find the value

Q: V3r-1 7. lim X- sin? x-cos(2x)

A:

Q: sin 2x tan 3x (a) lim

A:

Q: (b) Find lim, 0 xª cos 2.

A:

Q: nx + 1 If lim エ→+0 = 9, find n. 1 %3D nx -

A:

Q: Evaluate

A: It is given that,limx→-∞x2e-xWe have to evaluate it.

Q: Q27. The value of lim x-0 (1+x)5-e5x+sin x² x2 is? →

A:

Q: t x sin(t + 1) lim --1 t +1

A: Given : limt→-1t×sint+1t+1

Q: Find lim sin (4 T x). I -3

A:

Q: cos(x) - 1+ lim 14x4 Limit %3D

A: We need to evaluate the value of the following limit limx→0cosx-1+x2214x4

Q: (x² - 3) 7. Build a table to estimate lim sin x

A:

Q: х(4+sin 6x) 3. lim X→+0 х+1

A:

Q: 68. (x) = sec x %3D lim a. As x- f(x)→ b. As x→2 f(x) → /2

A:

Q: 7. *Find the values of a and b lim sin(ax-2a) x-2 = 3 %3D x-2

A:

Q: dx X XP (x - 1)ule a-1 lim

A: Given limit lima→1∫0aln1-xxdx. The objective is to evaluate the limit.

Q: 10 sin(4x³) 12x8 lim X→0

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Which of the following will make limx→c f(x) and f(c) equal? limx→2 : (x²+x-6) limx→–1 (x³ − 2x + 3)…

A:

Q: Evaluate

A: Our Aim is to evaluate the limit given below:-limx→0tan (2x)x-(i)