cos( sin 8x 8 Also, u = x. Therefore, the differential is du = dx dr Step 2 To find the integral J x cos 8x dx by the parts formula, use u = x and v = Apply the rule of integration by parts. Judv 1 dv = uv - -11 du U Step 3 Substitute the expressions for u and v in the integral. √x cos x cos 8x dx = ( sin( J») -/ Apply the constant multiplication rule to integrate the right side and simplify. x cos 8x dx = sin 8x - (cos 8x) + C COS 8 1 sin 8x + V 8 x) dx 8 S cos 8x + C 18 sin 8x, as used in the previous step. x) dx sin(
cos( sin 8x 8 Also, u = x. Therefore, the differential is du = dx dr Step 2 To find the integral J x cos 8x dx by the parts formula, use u = x and v = Apply the rule of integration by parts. Judv 1 dv = uv - -11 du U Step 3 Substitute the expressions for u and v in the integral. √x cos x cos 8x dx = ( sin( J») -/ Apply the constant multiplication rule to integrate the right side and simplify. x cos 8x dx = sin 8x - (cos 8x) + C COS 8 1 sin 8x + V 8 x) dx 8 S cos 8x + C 18 sin 8x, as used in the previous step. x) dx sin(
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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