Question
Asked Sep 13, 2019

Cos2x+cos6x=2cos4xcosx

check_circleExpert Solution
Step 1

We know,...

(b) 2cos
cos (a) cos
COS
Now
L.H.S
cos2x + cos6х
(14)cos 2)
2х+6х
2cos
COS -6x
8x
2cos
COS
=
= 2cos(4x)cos(-2x)
(cos(-a)cosa)
2cos(4x)cos (2x)
= R.H.S
Hence, proved.
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(b) 2cos cos (a) cos COS Now L.H.S cos2x + cos6х (14)cos 2) 2х+6х 2cos COS -6x 8x 2cos COS = = 2cos(4x)cos(-2x) (cos(-a)cosa) 2cos(4x)cos (2x) = R.H.S Hence, proved.

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