(cos2y-3x²y-)dx + (cos2y-2xsin2y-2x°y)dy = 0

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Q: cos z) dz 4 5.

A: Given: - The indefinite integral is, ∫e2zcos14zdz To find: - The solution of the given integral.

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Q: 2. ( sin32x dx cos 2x

A: We have to integrate.

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A: Integrate

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Q: .3 Cos x + cos x dx Vsin a 3,

A: Given…

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Q: 3) y sin-ly² dy

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Q: +3x2 B) Find dy/dx if : (****")) (v)² = sin (cos³

A: Differentiation chain rule

Q: y = sin(3 – 4x)" %3D

A: Apply the chain rule of derivatives, If y = f(g(x)), thendydx=d(f(g(x))d(g(x))×d(g(x))dx

Q: (2x-ィ) cos 3x dx

A: The given function is, ∫(2x2-1) cos3x dx. Obtain the value of the integral ∫(2x2-1) cos3x dx.…

Q: 3. y" y'-y = cos(5t) - sin(5t); y(0) = 2 and y'=5

A: First find the commentary function then particular integral and then use the initial conditions as…

Q: (cos2y — 3x*у-)dx + (cos2y — 2хsin2y — 2x3у)dy — 0

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Q: I. Find dy -and simplify the result whenever possik dx 1. у%3Dsec3 2х - 3sec2x 2. y = sin (x + 4 )…

A: Given; 2) y=sin(x+4) cos(x-4) 3) y= -3 cot5(x/3)/5 + cot3(x/3) -3cot(x/3) - x.

Q: of degree 2 )dx is equal

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Q: (- + 2 cos 2x ) dx + (- - 2 sin 2y ) dy = x2

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Q: cos2x a) -.dx,b) xe*. dy Į sin2x. [In(sin2x)]² + sin2x 0.

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Q: Find d-/dx² at the given point without eliminating the parameter. x=0+ cos0 and y=1+sin0 ; 0 =a/6,

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Q: y=cos(4x) /cos22x-4sin2x cos2x differentiate?

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Q: y=2(21,2-1 + arctan x) 2 2 x-1

A: Please see the whiteboard.

Q: 2 | (sin³x cos x + sinxcosx)dx 7/2 π

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Q: 1 Cos(2x)dx 0. (i) Using composite Trapezoidal rule with n = 2, 4

A: As per the policy of bartleby the provisions is to solve only one question at a time So I am solving…

Q: π/2 sin3 (4 ) αθ - π/2

A: To evaluate the following integrals

Q: 7T 2 Find 35 cos(7x) dx 5π 2 7T 2 35 35 cos(7x) dx = -5π လ

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Q: 5-2x dy if y = cos Find dx %3D 5+ 2x

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Q: (T/3 4 sinx -dx 1-4cosx 1-

A: As per our guidelines we are supposed to answer only one question. Kindly repost other question as…

Q: 2T sin (2) dydx 0,

A: To evaluate the double integral, ∫π2π∫0x3sinyxdydx.…

Q: I3Jsin'x cos x dx .6,

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Q: Find dy/dx at the given point 6x2-5y3=2x-5y at (0,1)

A: First differentiate the equation and then substitute the value of x as 0 and y as 1.

Q: Evaluate dy/dx if y = (sec2x - tan2x)/(2cos2x-1)

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Q: 1. Ssin (2x-1)cos (2x-1)dx

A: 1) Evaluate: ∫sin42x-1cos32x-1dx

Q: 23. cos (3z + 4) dz 25. sec2 (3x + 2) dx

A: A

Q: (一 - dx t - 3 X*cos(3)-4-2 ) -)dy=0 = 0

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Q: 7T, 0 cos( {*) cos(2y)dx 2gin( gx) sin (2) dy 77

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Q: 4. cos 4x cos 2x dx

A: The integration of the integral is cos(4x)cos(2x).

Q: Solve the equation [cos (2y) - (3x^2)(y^2)]dx +[cos (2y) - 2x sin 2y - (2x^3)(y)]dy = 0

A: To solve the given differential equation. First we check whether the differential equation is exact…

Q: х2 9 dy + sinx - у %3D0 dx

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Q: 5. y" – 2y' + y = 2sinx cosx y'(0) = 0,y(0) = 0 %3D | -

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Q: 1. y=1+sinx 2. y=(1/6)cosx 3. y=cosx+2

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Q: Find dy/dx if sin-(4y²) = 8x² – 5y3 Answer: Find dy/dx if tan- (xy²) = 3x² – 5y² Answer:

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Q: +3x2. Find dy/dx if: (y)² = sin5(cos³(- -)) 2 %3D

A: Given: (y)2=sin5cos3x7+3x22 ----(1) To find: dydx Let u=x7+3x22 , v=cos3u w=sin5v Now equation (1)…

Q: 2cosx dx 2 1+(sinx)²

A: Please refer the attached image for complete solution.

Q: -3л/2 сл/2 2. I cosysin2x dy dx

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Q: (2x–1)(cos(/3(2x–1)3+6)dx V3(2x-1)3+6

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Q: 2. sin3x dx + 2y cos³3x dy = 0

A: Given- sin3xdx+2ycos33xdy=0 To Solve- The above differential equation.

Q: 3. y" + 2y' + 5y = t cos(5t) - 6,y(0) = 1, y'(0) = -2

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