cosx sin'x = 3.. 3. cos°x sin°x= 5. = (sin°x- sin°x)cosx

Q: Use a calculator to compute sinhx and coshx for x = -3, 0, 5.

A: We use a calculator to find the values.

Q: [sin³ 4x cos 4xdx

A: We can find the answer as below.

Q: cosx+sinx=cos(2x)  Prove that tanx=-1

A:

Q: (g) tan sec2 dx (c) sin“(3x) cos (3x) dx CoS'

A: Given: I1=∫sin43xcos33xdx, I2=∫tan4x2sec2x2dx

Q: 11.) cos os (sin-1 -tan-1%) 12.) tan (arccos %- arcsin (-12/13))

A:

Q: 6. cos x(csc x secx) secx) cotx

A:

Q: If y=sin 2x sin 3x sin 4x then find y''

A:

Q: sinr cos (x - y) - cosx sin (x - )

A: As we know that the trigonometric identities: sinA-B=sinAcosB-cosAsinB   Given:…

Q: Find the period and amplitude of the function. 2n y=-4 sin x- 3 Give the exact values, not decimal…

A: If y=AsinBx is a function then its amplitude is A and its period is 2πB.   The given function is…

Q: Evaluate sin 2x -dx sin x sin x+- 3 3

A:

Q: Sec (Cosx) dydx 1- Sin

A:

Q: |sin³ xdx

A: I=∫0π2sin3x dx =∫0π2sin2x·sin x dx =∫0π2(1-cos2x)sin x dx Let  ⇒cos x=t⇒-sin x dx=dt⇒sin x dx=-dt…

Q: Vtan XP sin X cosX

A:

Q: Find 7 sin (7x) dx

A: According to question,Given Integral,Let I = ∫7 sin27x dx

Q: Express sin6 Oin terms of powers of sin Oonly

A: We have given,  sin6θ we have to express it in the term of sin only.

Q: Find the possible values of x in |coshx -sinhx| = 2 Isinhx coshx

A: Given,           coshx-sinhxsinhxcoshx=2

Q: Find the derivative of tan−¹(x).If you use the identity 1 + tan²(x) = sec²(x), you can write the…

A:

Q: Verify identity tan2 2x + sin2 2x + cos2 2x = sec2 2x.

A: To verify: tan2 2x + sin2 2x + cos2 2x = sec2 2x WKT cos2x+sin2x=1 x refers to any number, Replace x…

Q: If y = sin2x sin3x sin4x then find y"

A: Explanation of the answer is as follows

Q: Find an equation of a tangent function with period 5 and phase shift TC

A:

Q: 7. csc'x - cotx + tan'x CoSx - sin?xcosx

A:

Q: ∫sin5(6x)cos(6x)dx

A: ∫xn=xn+1n+1+C

Q: IF 3 TANQ = 3SINQ FIND THE VALUE OF SIN²Q - COS²Q.

A:

Q: Sine- -Cos zo

A: Using trignometric property

Q: 1-cosx sinx

A: Using Trigonometry property,

Q: 15.sin2x secx- cscx =0

A: The value of x is π/4 + nπ/2

Q: - cosx = sinx tanx cosx

A:

Q: 5. y = -2 cos x - - Amplitude: Phase Shift: Period:

A:

Q: If x= ln (sec θ +tan θ) , show that sec θ = cosh x .

A: It is given that  x= ln (sec θ +tan θ)

Q: sin 2x cos 3х dx

A:

Q: 12) Given y = 2 sin2x Period = b 3D Period = 1-- -1- -2

A: Solution: Give y=2sin2x Now use the form [a sin(bx-c)+d] That implise a=2 and b=2   Period =…

Q: tan x dx sec x+4 cosx 5.

A:

Q: 5) [ Arc sin- xdx

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: S(sec; - sin) do

A: We know that integration power rule is  Integration of (xn) = xn+1/n+1.   Here i attached the…

Q: cos xdx 54-sin²x

A:

Q: Find the exact value of the expression. sin-(- v3/2)

A: GivenSin-1-32By simplification we get that-Sin-132=-arcsin32 Now look the below table  x…

Q: If y = sin 2x sin 3x sin 4x then find y".

A:

Q: 1-cos2.x sin 2.x : tanx

A: Given- 1-cos2xsin2x : tanx To Simplify- The above expression. Formula Used- cos2x=1-2sin2x and…

Q: If sinhx=-1÷2,then coshx is

A:

Q: What is the exact value of cos (tan ¹(-1)) 2 -? sin cos 08-¹(- +/-))

A: We have to find the exact value of costan-1-1sincos-1-32.

Q: sin 3x cos“ 3xdx

A:

Q: cos 2x cotx-1 1+sin 2x cotx+1 20

A:

Q: cos 2x sin2x Cotx

A: Solution: The objective is to find the value of the given expression

Q: • tan xcos x = cotx %3D cScx • (1- sinx)[1+ sin(-x)] = •csc?x - cot2x =

A: We need to simplify the given trigonometric expressions.

Q: Differentiate x sin-1 (x) with respect to sin¯'x. х.

A:

Q: # 2: Given: y = - sin ( x + 3 Find the Period: Amplitude: Phase Shift: Vertical shift:

A:

Q: -CSCX · COSX = -Cotx - 1 cosxsec2x = COSX 1 1 sec2 x+cot2 x csc2 x+tan2 x CScx 1+ cot2 x = sinx

A: NOTE: Refresh your page if you can't see any equations. .

Q: S sin æsin4xdx

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: Evaluate 0 -1 sin ¹(3x) dx.

A:

Q: Find sin 0 and tan 0 if the terminal side of 0 lies along the line y = -7x in QII. sin 0 = tan 0:

A: Given that terminal side of ϑ lies along the line y = -7x. Note that the slope of the line y = -7x…