cosxtanx - cos x= 0 + O 0+n,+ 2nx 5я O O+*5, + 2nx 5я

Q: V34 cos co - 59.036°) = 4 cos co -59.036°) V34 o - 59.036° - Cos" (会 o -59.036= 46.686 0 = ° 105.才22…

A: The objective is to find the value of theta.

Q: 6 sin(47y)sin(5y)

A:

Q: tan(tan3x)dx Evaluate: cos-3x -In |sec (tan3x)| + C (B ® - in [cos(tan3x)| + C © - sin( tan3x)| + c…

A: We need to evaluate the following integral I = ∫tantan3xcos23xdx…

Q: 1+cosx Evaluate V2-2 cosx

A: 3rd option correct

Q: √2 cos x csc x=2 cos x

A: 2cosxcscx=2cosx

Q: Setting x= cos or cosho show that Tn(x)==[(x + √X²_₁ )² + (x-√x ²₁ ²]

A:

Q: sec x - csc x Rewrite the expression Fin terms of cos x. cot x – 1 1 cos x cos x Option 1 Option 2 1…

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Q: 4 cos x + 2 sin r = 2 COS

A: As we know, Sin2x + cos2 x = 1 Since the interval is not given so we have to find general solution

Q: Evaluate (4 sin² x cos² x dx sin 2x cos 2x A) 1/2 In/cos2x| + C O B) -1/2 In/cos2x| + C O C) NONE OF…

A:

Q: JOTICE sinx= IC X = 2. -Cos X OTICE

A: sin(x)= cos(x) when x= π/4

Q: Simpliy Hhe fAllowing Cos 180°. Sin 25. Cos 80 Sin 170°. fan135 tan 225 . Sin (g0°40) + Cos (180 ).…

A:

Q: 4sin(x)cos (x)+2sin(x)-2cos(x)-1=0

A: I am going to solve the given problem by using some simple calculus to get the required result of…

Q: */2 Cos Jo

A:

Q: +sin(n")n-1 n6.1+cos(n2)n®+2 4. 2 9) Et sin (n* cos(n)

A: We have to use limit comparision test for checking divergence

Q: 4. Find the exact value of cos *x- sin "x-cos (2x). 4 cos x- sinx- cos (2x) = (Simplify your…

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Q: 2 cos I Use a counter-example to show that cos 2x

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Q: 1. Solue cos ( x - 2) = 7

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Q: cos x = 1/2 Find x

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Q: Solue [2 cos 0-31-5 from 0 02360°

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Q: cos(2æ) Select an identity for cos(x) O cos(x) · cot(x) – sin(æ) O csc(x) O cos(x) – sin(æ) · tan(x)…

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Q: sin(x) cos(x) xp (cos(x))2

A:

Q: – 1) sin a cos a - sin æ 9(cos² e – 1) O 9 tanx + 9 sec a O 9 cot a + 9 cscx O 9 tana + 9 csc a O 9…

A:

Q: y = 7 cos(x), y = 7 - 7 cos(x), 0 ≤ x ≤ π

A: The given equations are: y=7cosx, y=7-7cosx, 0≤x≤π To find the area of the region between the curves…

Q: 6. Rewrite over a common denominator: 1 /1 - cos v + 1/ 1 + cos v

A: We have given 11-cosv+11+cosv Then, 11-cosv+11+cosv=1+cosv+1-cosv1-cosv1+cosv=21-cos2v=2sin2v

Q: a. [CO²2 2 cos²x√4 tan x tan² x da

A:

Q: Prove or disprove.

A:

Q: cos?x- 3 cos x =- 1 on the interval [0,1).

A: Given- 2cos2x-3cosx=-1  To find- the value of x on the interval [0,π) Concept Used- The above…

Q: Describe the difference between  y=1/cos x  and  y=cos^-1

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Q: sin ²e + cos²e =(1)". if n>1

A:

Q: sin(cos-(0.7068)) O - 1.2926 O 0.7074 2.7074 -0.2926 1.7074

A:

Q: sin(cos (0.5354)) = O 0.8446 O 1.8446 O -0.1554 O -1.1554 O 2.8446

A:

Q: cos (0) tan (0)+3tan(0)=0

A: cosθtanθ+3tanθ=0

Q: cos ax dx = xe", a 2 0. (or) Evaluate x' +1 cos ax 2: Prove that x +1

A:

Q: 3) cos -40 + 4) 1=-1 + 2tan -46

A: 1.

Q: Simplify (cos x- sin x)(cos x+ sin x). sin x cos x O 2 cos x-1 2 cos x+1

A: Given: cosx-sinxcosx+sinx

Q: 1 tano + tano = 1 sin cose

A:

Q: Cos u= 8/9. Evaluate cos v

A:

Q: Verify the identity.

A: Given: verify the identity cos3x+cos5xcos3x-cos5x=cotxcot4x we know that…

Q: |5x sinx dr = 5x cosx +5 sinx +c -5x cosr +5 sinx +c None 5x cosr - 5 sinx +c

A:

Q: Cos 0 do |3| 3 6. 0.

A: ∫06πcosθdθ    = sinθ06π    = sin6π-sin0    = 0 - 0   = 0

Q: 8(x)=cos x,[0,2=]

A:

Q: 2 cos 2 ( x ) − 7 cos ( x ) + 5 = 0

A: Topic - trigonometric Equations Put cos 2x = 2 cos2 X-1

Q: 8(cos² z – 1) sin z cos z – sin z

A: Given,           8cos2x-1sinxcosx-sinx

Q: (a). Find a common denominator for COSX |- COSX and 1- COS x COS x –COS X COSX = cosx-coseX COS X…

A: a To find a common denominator for 1cos x and cos x1-cos x.b To expand cos x+tan x2 and to simplify.

Q: TI tant@-2 tan Bzl show that 2cose - Cos"B2o

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Q: #/2 sin " x 2: Evaluate 20 sin ° x+ coSx

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Q: 2 cos(x) – 1 = 0

A: We have to find the value of x.

Q: 5(cos²æ – 1) sin x cos x sin x - ||

A: Using trigonometric formula, given trigonometric function is simplified.