coth“ (sin 3z) -dz /1– tanh² 3z 12)

Q: Siven cos x E and π x<. 5 ", find tan(2x) %3D

A:

Q: (sech°x)/1+ sin? if y = dx dy Find tanh°x

A: Given:-       To find:- dy/dx

Q: 1- tanhx = sech x

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: 5. y = tan- (a) 6. y = 4x sin (3x - 9) 7. y = sinh (4x – 1)

A:

Q: sec?x Integral tanx

A:

Q: lim, 0 tan² (7x) cot(11x) (r+7)sinx

A: Given: The limit as limx→0tan27xcot11xx+72sin x. To find: The main aim is to find the value of the…

Q: sin 2 2xcos 2x cos 2x dx

A:

Q: 2 (tan²x + 1)√sin2x.dx= (tan², 0

A: Find your answer below

Q: | sin(4z) cos(7z) dz.

A: To find:∫sin4zcos7zdz

Q: 2. S tane sec4 0 d0

A:

Q: olve the equation on the interval 0s0<2x V2 sin0- sin 0 = 0

A:

Q: can you prove it, please ? cosh 2x=sinh^2x+1 = 2 cosh^2-1

A:

Q: inetgrate sin^2(x)csc^2(2x)

A: Given: Let I=∫sin2xcsc22xdx To Find: To integrate the given integration.

Q: 6. G) sec 4 tan .3. dx 3 (),

A: Consider the given integration ∫tan6x3sec4x3dx

Q: (3.2 cos 2x+2 -dx. 1.8 1+ In x Use NINT on the calculator to evaluate:

A: We have to evaluate ∫1.83.2 cos 2x + 21 + ln x dx.

Q: 10x 19) y Sin'(5x') (ans.: JI-25 x' 20) y= Cot ) (ans.: 1+ x' 6x' 21) y=tan'V4x'- 2 (ans.: (4x'-1…

A: As per guidelines we can only solve first question or first three subparts of the question, I am…

Q: sin(2x) cos(2x) dx 1+ cos(4x)

A: The complex form of integral can be converted to simple integral using integration by substitution…

Q: 3. sin 3z cos 5z dr

A: Here we have to evaluate I=∫sin3xcos5xdx

Q: arc cos XY VI-x²

A: “Since you have asked multiple question, we will solve the first question for you. If you  want any…

Q: 13. sec*0 sin 8 de

A:

Q: tion for sin x= 0.3

A:

Q: (2 cos 2x+ 3 sin 2.x) 7. evaluated at x = 1 rad

A: Given query is to find the value of the expression at x = 1.

Q: 7/4 (sec² x – sin x)dx

A: 1. ∫sec2x dx=tanx 2. ∫sinx dx=-cosx 3.∫(u±v)dx=∫u dx±∫v dx 4. ∫abf(x) dx=F(b)-F(a), where ∫f(x)…

Q: ( sin (In 2x) - cos (in 2x))? +x dx 2x

A: Let's find.

Q: Find y': y = cot 0 sin 0 O sin² 0 1-tan²0 O1+sin² 0 cos³0 O-1-cos² e sin³0 3

A:

Q: integral sec2(?) tan2(?) d?

A: Given that sec2?tan2?d?To find : Integral Solution :∫sec2?tan2?d?Let, tan?=tsec2?d?=dt∫t2dtt33+c

Q: 1-tanh² x sinh(2x) O cosh(2x) O sech(2x) O csch(2x) O Leave Question O |

A: To compute1+tanh2x1-tanh2x

Q: 1-Sinx finel y 14 Sinx

A: Consider the given function, y=1-sinx1+sinx use the quotient rule of the differentiation which…

Q: 7- I = [sec(2x) tan(2.x)dx cos(2x) 8- I = dx 4-sin (2x) csc (In(x)) 9. I: dx

A:

Q: find

A: Given,           y=2sin22x*3tan-12x

Q: sin $3xcos 3x dx

A:

Q: sin(2r) cos(2x) +1 2. Prove: csc(2x) + cot(2r). %3D COS

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Q: šx<2a . dation where 1 1. sin x = 2 2. 3tanx-1=0 3. 2cosx=cosx

A: We will find the values.

Q: 12 tan (4.x) sec (4x) dx S cos(11x) sin(2r) dx COS

A: Given that integration and we solve this integration by using general formulas of integration. Here…

Q: What is the antiderivative of sin^2(x) + 2sin(x)?

A: Antiderivative of sin^2(x) + 2sin(x) is given by,  ∫[ sin2x + 2sinx ]dx =∫sin2x dx + ∫2sinx dx

Q: = tanh (2x) Use the definition of the hyperbolic functions to prove the identity 1– cosh?(2x)

A: 1-1cosh22xUse the Hyperbolic identity:  1coshx=sechx=1-sech22xUse the Hyperbolic identity:…

Q: S sin x In(1 + sin x) dx

A: Given : Integral of sinx ln(1+sinx) dx The genral formula for the integration of function is as…

Q: sin 2t cos 2t dt 1 +3 cos 4t

A: Integration is the process of finding the anti-derivative function of the given function. The…

Q: ating / * sin (2x)cos(2x) dr by substitution, if u= sin(2x) th

A:

Q: 1. sin (3z) cos5(3z)dz

A: Note -  Acc. to Bartleby guidelines, we are supposed to do only one question . If you want more to…

Q: X= sin 2tS In %3D Find dw 2- Cost

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Q: 3. у %3D tan1(sinh 2x) Зсosh-1 (csc) 4. у %3 CSC

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Q: sin(13z) sin(9z) dz

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: If siny=x^2 Then find the value of cos2y

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Q: Solve y' = y3 cos x (Show clear work!)

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Q: sec(x)cos(3x)=0 from [-pi/2, pi,2]

A: sec x cos 3x=0          [-π/2,π/2] sec x (4 cos3x - 3 cos x) = 0 [cos 3x= 4 cos3x - 3 cos x] 4 sec x…

Q: If sinx = siny = a and cosx = cosy = b,then cos(x-y) is

A: