Cov(ax + b, cY + d) = - E(ax + b)E +, )-)) + adx + bcY + bd - ((аЕX) + b) + adE(X) + bcE(Y) + bd = + adE(X) + bcE - acE(X)E | - E(X)E = acCov(X, Y) p) Use part (a) along with the rules of variance and standard deviation to show that Corr(ax + b, cY + d) = Corr(X, Y) when a and c have the same sign. , CY + Cov Corr(ax + b, cY + d) = Oax + bº cY + d Y) lal|cloxoy Corr(X, Y) Ja||c| = Corr(X, Y) =) What happens if a and c have opposite signs? ас O when a and c differ in sign, ac is negative and = -1. Therefore, Corr(ax + b, cY + d) = -Corr(X, Y). lallc| ас O When a and c differ in sign, ac is positive and - = 1. Therefore, Corr(ax + b, cY + d) = -Corr(X, Y). la||c| ac O when a and c differ in sign, ac is positive and = 1. Therefore, Corr(ax + b, cY + d) = Corr(X, Y). la||c| ас O When a and c differ in sign, ac is positive and = -1. Therefore, Corr(ax + b, CY + d) = -Corr(X, Y). Jallc| O When a and c differ in sign, ac is negative and ас = -1. Therefore, Corr(ax + b, cY + d) = Corr(X, ). Ja||c|

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 32E
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Related questions
Question
(a) Use the rules of expected value to show that Cov(ax + b, cY + d) = ac Cov(X, Y).
Cov(ax + b, CY + d) = E
- E(ax + b)E
])-)
+ adx + bcY + bd -
(aE(X) + b) CE
=
= acE
+ adE(X) + bcE(Y) + bd
+ adE(X) + bcE
= acE
acE(X)E
1))
=
— асCov(X, Y)
(b) Use part (a) along with the rules of variance and standard deviation to show that Corr(ax + b, cY + d) = Corr(X, Y) when a and c have the same sign.
co(
b, cY +
Corr(ax + b, cY + d) =
Oax + bº cY + d
Cov(X, Y)
la||clox0y
Corr(X, Y)
lallc|
= Corr(X, Y)
(c) What happens if a and c have opposite signs?
ac
O When a and c differ in sign, ac is negative and
= -1. Therefore, Corr(ax + b, CY + d) = -Corr(X, Y).
la||c|
ac
O When a and c differ in sign, ac is positive and
= 1. Therefore, Corr(ax + b, cY + d) = -Corr(X, Y).
Jal|c
ас
O when a and c differ in sign, ac is positive and
= 1. Therefore, Corr(ax + b, cY + d) = Corr(X, Y).
lal|c
ac
O when a and c differ in sign, ac is positive and
= -1. Therefore, Corr(ax + b, cY + d) = -Corr(X, Y).
la||c|
ас
O When a and c differ in sign, ac is negative and
= -1. Therefore, Corr(ax + b, cY + d) = Corr(X, Y).
lallc|
Transcribed Image Text:(a) Use the rules of expected value to show that Cov(ax + b, cY + d) = ac Cov(X, Y). Cov(ax + b, CY + d) = E - E(ax + b)E ])-) + adx + bcY + bd - (aE(X) + b) CE = = acE + adE(X) + bcE(Y) + bd + adE(X) + bcE = acE acE(X)E 1)) = — асCov(X, Y) (b) Use part (a) along with the rules of variance and standard deviation to show that Corr(ax + b, cY + d) = Corr(X, Y) when a and c have the same sign. co( b, cY + Corr(ax + b, cY + d) = Oax + bº cY + d Cov(X, Y) la||clox0y Corr(X, Y) lallc| = Corr(X, Y) (c) What happens if a and c have opposite signs? ac O When a and c differ in sign, ac is negative and = -1. Therefore, Corr(ax + b, CY + d) = -Corr(X, Y). la||c| ac O When a and c differ in sign, ac is positive and = 1. Therefore, Corr(ax + b, cY + d) = -Corr(X, Y). Jal|c ас O when a and c differ in sign, ac is positive and = 1. Therefore, Corr(ax + b, cY + d) = Corr(X, Y). lal|c ac O when a and c differ in sign, ac is positive and = -1. Therefore, Corr(ax + b, cY + d) = -Corr(X, Y). la||c| ас O When a and c differ in sign, ac is negative and = -1. Therefore, Corr(ax + b, cY + d) = Corr(X, Y). lallc|
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