Answe the Question Create a function that takes a list of functions and sorts them in ascending order based onhow many calls are needed for them to return a non-function.Examplesf1 = => "hello"// f1() → "hello"f2 = => => "edabit"// f2() () → "edabit"f3 = _ => => => "user"// f3() () () → "user"funcSort([f2, f3, f1]) → [f1, f2, f3]// [f2, f3, f1] [2, 3, 1] → [1, 2, 3] → [f1, f2, f3]-funcSort([f1, f2, f3])// [f1, f2, f3]-[f1, f2, f3][1, 2, 3] - [1, 2, 3] → [f1, f2, f3]funcSort ([f2, "func"])// [f2, "func"] --["func", f2][2, 0] 1 [0, 2] ["func", f2]

function funcSort(arr) { return arr.sort((a, b) => { let aCalls = calls(a); let bCalls =…

Create a function that takes a list of functions and sorts them in ascending order based on how many calls are needed for them to return a non-function. Examples f1 ==> "hello" // f1() → "hello" f2 = => // f2() () "edabit" => "edabit" f3 = => => => "user" // f3() () () → "user" funcSort ([f2, f3, f1]) → [f1, f2, f3] // [f2, f3, f1] [2, 3, 1] [1, 2, 3] 1 funcSort ([f1, f2, f3]) → [f1, f2, f3] // [f1, f2, f3] - [1, 2, 3] [1, 2, 3] - funcSort([f2, "func"]) // [f2, "func"] [2, 0] - ["func", f2] - - [f1, f2, f3] [f1, f2, f3] [0, 2] - ["func", f2]

Create a function that takes a list of functions and sorts them in ascending order based on how many calls are needed for them to return a non-function. Examples f1 ==> "hello" // f1() → "hello" f2 = => // f2() () "edabit" => "edabit" f3 = => => => "user" // f3() () () → "user" funcSort ([f2, f3, f1]) → [f1, f2, f3] // [f2, f3, f1] [2, 3, 1] [1, 2, 3] 1 funcSort ([f1, f2, f3]) → [f1, f2, f3] // [f1, f2, f3] - [1, 2, 3] [1, 2, 3] - funcSort([f2, "func"]) // [f2, "func"] [2, 0] - ["func", f2] - - [f1, f2, f3] [f1, f2, f3] [0, 2] - ["func", f2]

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter6: User-defined Functions

Section: Chapter Questions

Problem 17PE

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