Create dihybrid crosses from the following information: 39. A heterozygous tall double eye individual with a short single eyed individual. Draw your chart below. a. What are the two parents genotypes: b. What are their children's genotypes: С. What are their children's phenotypes:
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- Cross 1 AaBb x AaBb Cross 2 AaBbCc x AaBbCc a) Please use a branching diagram to find the genotypic ratios of the offspring of cross 1 illustrated above and complete with the resulting genotypes and ratios. How many different genotypes are there in the offspring of this cross? [ ] Genotype ratios for the offspring of Cross 1 (please indicate both the ratio and the genotype for each one: e.g.: 3AABB:1aabb, etc): [ ] b) Please use a branching diagram to find the phenotypic ratios of the offspring of cross 2 and complete below the resulting phenotypes and ratios. How many different phenotypes are in the offspring of this cross [ ] Phenotype ratios for the offspring of Cross 2 (please indicate both the ratio and the phenotype for each one using D and R for dominant and recessive phenotypes respectively, for example 1DDD:2DRR, etc.): [ ] c) What mathematical operation are you using to calculate the ratios for multiple genes and what…In guinea pigs, black hair colour (B) is dominant and brown hair colour (b) is recessive. Long hair (L) is dominant and short hair (l) is recessive. Answer the following questions: (a) Find the gamete types for the cross: BbLl X BbLL (b) What are the phenotypes of the parent generation? (c) What are the genotypes and phenotypes of the F1 generation?What will be the results of the following crosses, where N is black, n is brown, L is short hair and l is long hair. Make the tables and the corresponding explanation: 1. Crossing a Nnll woman dog with a Nnll dog. 2. Crossing a NnLl woman dog with a NnLl dog 3. Crossing a woman dog nnLl with a dog NNll
- Fruit flies can have straight wings (S) or curly wings (s), and they can have be female XX or male XY. (A) For a standard monohybrid cross (Ss ´ Ss), what proportion of the offspring will have the genotype ss? (Express the proportion as a simple fraction) (B) For the following cross (SsXX ´ SsXY), what proportion of the offspring will have the genotype Ss? (Express the proportion as a simple fraction) (C) What proportion will have the genotype XX? (Express the proportion as a simple fraction) (D) What proportion will have the genotype SsXX? (Express the proportion as a simple fraction)SHOW YOUR WORKA cross between individuals with the genotypes AaBb and aabb produces 1000 offspring. The aabb class contains 380 individuals. a. Are genes a and b linked? Explain your answer. b. What is the linkage configuration in the heterozygote parent. c. What types of gametes will be formed by the heterozygote parent and in what proportions? Give only the allele compositions of the gametes in brackets and their relative proportions.The F1 from a cross of AABB x aabb is testcrossed, resulting in the following phenotypic ratios: AB 308 Ab 190 ab 292 aB 210 (1) what are the genotypes for the listed phenotypes? (2) why aren't the phenotypes in a 1:1:1:1 ratio? (3) what is the frequency of recombination between genes A and B?
- b) You test cross an F1 fish (with genotype BbCc) and obtain 1000 offsprings in F2 generation with the following results: 474 Bbcc, 480 bbCc, 20 BbCc and 26 bbcc.1. Create and fill in a Punnet square for this cross.2. What type of cross is it? 3. Are these loci linked? 4. What are the two parental classes and the two recombinant classes of offspring? 5. What is the percentage of recombination between these two loci? Show your calculations. 6. How many map units apart are they?Calculate the Chi square for cross 1 and cross 2 from the data in the attached image. Cross1: Phenotypes Ratio Observed Expected (O-E)2/E Totals X2 = Cross 2: Phenotypes Ratio Observed Expected (O-E)2/E Totals X2 =A geneticist crosses two yellow mice with straight hair and obtains the following progeny: 12 yellow, straight 16 yellow, fuzzy 14 gray, straight 112 gray, fuzzya. Provide a genetic explanation for the results and assign genotypes to theparents and progeny of this cross.b. What additional crosses might be carried out to determine if yourexplanation is correct?
- The genotypes of F1 individuals in a trihybrid cross are LlMMNn x llMmNn. What is the probability that the F2 offspring will have an LlMmnn genotype? Use the forked-line method in solving the problem.In the self of a polygenic trihybrid R1/r1 ; R2/r2 ; R3/r3,use the product and sum rules to calculate the proportion of progeny with just one polygene “dose.”If two gene pairs A and a and B and b are assorting independently with A dominant to a and B dominant to b, what is the probability of obtaining: a. an AB gamete from an AaBb individual? b. an AABB zygote from an AaBb x AaBb cross? c. an aaBb offspring from an AaBB x aabb cross? d. a phenotype aB from an Aabb x aaBb cross? e. an ab gamete from an aaBB individual?