Create the function that takes a list of dictionaries and returns the sum of people's budgets . Example: get_budgets([ {“name”: “John”, “age”:21, “budget”: 23000}, {“name”: “Steve”, “age”:32, “budget”: 40000}, {“name”: “Martin”, “age”:16, “budget”: 2700} ])→ 65700

Create the function that takes a list of dictionaries and returns the sum of people's budgets . Example: get_budgets([ {“name”: “John”, “age”:21, “budget”: 23000}, {“name”: “Steve”, “age”:32, “budget”: 40000}, {“name”: “Martin”, “age”:16, “budget”: 2700} ])→ 65700

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter10: Pointers

Section: Chapter Questions

Problem 2PP

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Create the function that takes a list of dictionaries and returns the sum of people's budgets. Examplesget_budgets([ { "name": "John", "age": 21, "budget": 23000 }, { "name": "Steve", "age": 32, "budget": 40000 }, { "name": "Martin", "age": 16, "budget": 2700 }]) ➞ 65700 get_budgets([ { "name": "John", "age": 21, "budget": 29000 }, { "name": "Steve", "age": 32, "budget": 32000 }, { "name": "Martin", "age": 16, "budget": 1600 }]) ➞ 62600
PLEASE ANSWER QUICKLYSuppose you've written a function called mystery, which takes in a list of integers. You know that when you run the function with a list of 1000 elements, it always takes roughly 2 minutes to complete.
I need help with: •sort employees by rate of pay from high to low. •returns the average earnings of all employees •performs the search for a specific employee and returns the employee ID if found and 0 if not. •test the functions in the main function #include <iostream> #include <iomanip> #include <string> using namespace std; class Employee { private: int empNumber; // Employee number string name; // Employee name double hours, // Hours worked payRate; // Hourly pay rate public: Employee(int empN, string n, double h, double p) { empNumber = empN; name = n; hours = h; payRate = p; } Employee() { empNumber = 0; name = "No Name"; hours = 0; payRate = 0; } void setEmpNumber(int number) { empNumber = number; } void setName(string n) { name = n; } void setPayRate(double rate) { payRate = rate; } void setHours(double h) { hours = h; } int getEmpNumber() { return empNumber; } string getName() { return name; } double getHours() { return…
Create a function that accepts a string (of a person's first and last name) and returns a string with the first and last name swapped. Examples NameShuffle("Donald Trump") - "Trump Donald" NameShuffle ("Rosie O'Donnell") - "O'Donnell Rosie" NameShuffle ("Seymour Butts") - "Butts Seymour" • There will be exactly one space between the first and last name. In c#
This code is a part of a C dictionary. Please write the code for the below requirements. dict_get Next, you will implement: char* dict_get (const dict_t* dict, const char* key); This function goes through the list given by dict. If you use the above structure, this means starting at el = dict->head and checking each time whether the key at el is key; if it is not, we set el = el->next, until either key is found, or we reach el == NULL. To compare key with el->key, we need to compare one by one each character in key with those in el->key. Remember that strings in C are just pointers (memory addresses) to the first character in the string, so comparing el->key == key will not do what you want. So how do you even get the length of a string s? You would start at memory location s and advance as long as the byte at s (i.e. *s) is not the end-of-string marker (\0, the NULL character). This can get a bit messy, so luckily, you are allowed to use the string comparison…
Please enumerate all of the situations when invoking inline functions will not get the expected results.
#include <iostream> #include<string.h> //user-defined functions question! using namespace std; struct Books { char title[50]; char author[50]; char subject[100]; int book_id; }; int main() { double array1[5]= {13.768,4.0,88.7689,9.12,}; struct Books Book1; strcpy( Book1.title, "C++ Programming"); strcpy( Book1.author, "D.S Malik"); strcpy( Book1.subject, "C++ basics"); Book1.book_id = 6495407; ////Block#1////// int x=4; for (x; x>=0; x--){ cout<<array1[x]<<endl; //////////////////////////////// } cout<<"///////////////////////"<<endl; ////end of Block#1////// ////Block#2////// int sum=0, i=0; for (i; i<5; i++){ cout<<static_cast<int>(array1[i])<<" "; sum= sum+array1[i]; cout<<sum<<endl; } cout<< "final value of sum="<<" "<<sum<<endl; cout<< "the average value ="<<" " <<sum/5 <<endl; cout<<"//////////////////////"<<endl; //
Write a function called dict_intersect that takes two dictionaries as argumentsand returns a dictionary that contains only the key/value pairs found inboth of the original dictionaries.
Define the function lake_to_tli3_dict(readings) that takes a list of (lake_name, chla, tn, tp) tuples and returns a dict mapping lake names to trophic level index values. That is, the keys are lake names and the values will be TLI3 values. Notes: You will need to have import math as your first line of code. You must include and use/call the trophic_level_index function that you wrote in Question 1. trophic_level_index must still work as specified in Question 1. Lakes should be added to the dictionary in the same order as they appear in the readings list. If a lake appears in the readings list more than once, then the TLI for the last occurrence in the readings list should be the one that appears in the result. (This should happen naturally, since the lake name can only occur in the dictionary once.) For example: Test Result names_cnp_1 = [('Lake Brunner', 0.8, 218.0, 6.0), ('Lake Carrot', 5.1, 505.0, 18.5) ] tli3_dict = lake_to_tli3_dict(names_cnp_1 ) print(tli3_dict)…
It says there is an error in the class solution(the followup one), specifically in the read data function students[i].setGrade(); It says it is empty, but when I add the declaration char grade; to the function and change the statement to students[i].setGrade(grade); it still says there is an error. What does it need to be instead? Here is my code: #include <iostream> #include <string> using namespace std; const int numstudents = 20; class studentType { private: string studentFName; string studentLName; int testscore; char grade; public: void setName(string first, string last) { studentFName = first; studentLName = last; } void setScore(int score) { testscore = score; } void setGrade(char grade) { if (testscore >= 90) { grade = 'A'; } if (testscore <= 90 && testscore >= 80)…
HOW DOI I CALL THIS USING THE FUNCTION AFTER THIS getchar(); printf("Enter name : "); // Here we are using '^' to be able to use a space in the input - > scanf("%[^\ns]",p->name_1920213); printf("Enter last name : "); scanf("%s",p->lastname_1920213); printf("Enter mobile number : "); scanf("%ld",&p->contactnum_1920213); printf("Enter email : "); scanf("%s",p->email_1920213); void search_person()/* this function allows the user to search a specific contacts using the input name, last name, conatact number or email*/{ int choice_1920213; printf("\nChoose one option search for the contact details: \n\n1.First Name \t\t2.Last Name \n3.Mobile Number \t4.Email address \n ");scanf("%d",&choice_1920213); while(1) { switch(choice_1920213) /*Switch statement tests the value of a variable and compares it with multiple cases. Once the case match is found, a block of statements associated with that…
Write a program that reads in a line consisting of a students name, Social Security number, user ID, and password. The program outputs the string in which all the digits of the Social Security number and all the characters in the password are replaced by x. (The Social Security number is in the form 000-00-0000, and the user ID and the password do not contain any spaces.) Your program should not use the operator [] to access a string element. Use the appropriate functions described in Table 7-1.