CUMULATIVEAMOUNTCUMULATIVEPERCENTRETAINED,(c)=(b)*100/TOTALSIEVPERCENTAMOUNTRETAINED, g(a)RETAINED, g (b)PASSINGSIZE1%(d)=100 - (c)21518853/49801/223503/8119022051985101840401650100980200660PAN6015000TOTAL[7]

Answered: Image /qna-images/answer/c6acae88-9ae8-41a2-b0ed-fcc1ea2a4ea7.jpg

CUMULATIVE AMOUNT AMOUNT RETAINED, g (a) CUMULATIVE PERCENT RETAINED, (c)=(b)*100/TOT AL SIEV RETAINED, 9 (b) PERCENT PASSING E SıZ E 1% (d)=100 - (c) 215 885 3/4 980 1/2 2350 3/8 1190 4 2205 1985 10 1840 40 1650 100 980 200 660 PAN 60 13000 TOTAL

CUMULATIVE AMOUNT AMOUNT RETAINED, g (a) CUMULATIVE PERCENT RETAINED, (c)=(b)*100/TOT AL SIEV RETAINED, 9 (b) PERCENT PASSING E SıZ E 1% (d)=100 - (c) 215 885 3/4 980 1/2 2350 3/8 1190 4 2205 1985 10 1840 40 1650 100 980 200 660 PAN 60 13000 TOTAL

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Pressure and Stress

Question

CUMULATIVE
AMOUNT
CUMULATIVE
PERCENT
RETAINED,
(c)=(b)*100/TOT
AL
SIEV
PERCENT
AMOUNT
RETAINED, g
(a)
RETAINED, g (b)
PASSING
SIZ
E
1%
(d)=100 - (c)
215
1
885
3/4
980
1/2
2350
3/8
1190
2205
1985
10
1840
40
1650
100
980
200
660
PAN
60
15000
TOTAL
[7]

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