Current Attempt in Progress Evaluate the integral by applying the following theorems and the power rule appropriately. Suppose that F(x) and G(x) are antiderivatives of f(x) and g(x) respectively, and that c is a constant. Then: (a) A constant factor can be moved through an integral sign; that is, [ cf(x) dx = cF(x) + C. (b) An antiderivative of a sum is the sum of the antiderivatives; that is, [[f(x) + g(x)] dx = F(x) + G(x) + C. (c) An antiderivative of a difference is the difference of the antiderivatives; that is, - [[ƒ(x) − 9(x)] dx = F(x) − G(x) + C. The power rule: : [ x² dx = [ + C‚r ‡ −1. x²+1 r+1 NOTE: Enter the exact answer. - S [x−³ − 5x³ + 5x²] dx = +C

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
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Current Attempt in Progress
Evaluate the integral by applying the following theorems
and the power rule appropriately.
Suppose that F(x) and G(x) are antiderivatives of f(x) and g(x)
respectively, and that c is a constant. Then:
(a) A constant factor can be moved through an integral sign; that is,
[ cf(x) dx = cF(x) + C.
(b) An antiderivative of a sum is the sum of the antiderivatives;
that is,
[{f(x) + g(x)] dx = F(x) + G(x) + C.
(c) An antiderivative of a difference is the difference of the
antiderivatives; that is,
[[ƒ(x) − 9(2)] dx = F(x) − G(x) + C.
: [x³² dx =
NOTE: Enter the exact answer.
The power rule:
−3 – 5x³ + 5x²] dx ·
=
/ [x
x²+1
[ + C,r ‡ −1.
r+1
+C
Transcribed Image Text:Current Attempt in Progress Evaluate the integral by applying the following theorems and the power rule appropriately. Suppose that F(x) and G(x) are antiderivatives of f(x) and g(x) respectively, and that c is a constant. Then: (a) A constant factor can be moved through an integral sign; that is, [ cf(x) dx = cF(x) + C. (b) An antiderivative of a sum is the sum of the antiderivatives; that is, [{f(x) + g(x)] dx = F(x) + G(x) + C. (c) An antiderivative of a difference is the difference of the antiderivatives; that is, [[ƒ(x) − 9(2)] dx = F(x) − G(x) + C. : [x³² dx = NOTE: Enter the exact answer. The power rule: −3 – 5x³ + 5x²] dx · = / [x x²+1 [ + C,r ‡ −1. r+1 +C
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