C(x) = 400,000 + 120x + 0.003x" dollars to manufacture x smartphones in an hour. (a) Find the marginal cost function. 120 + 0.006x Use it to estimate how fast the cost is increasing when x = 10,000. $ 180 v per smartphone Compare this with the exact cost of producing the 10,001st smartphone. v per smartphone. The exact cost of producing the 10,001st smartphone is $ 180.006 The cost is increasing at a rate of $ 180 difference of $ 0.006 . Thus, there is a (b) Find the average cost function C and the average cost to produce the first 10,000 smartphones.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter3: Linear And Nonlinear Functions
Section: Chapter Questions
Problem 26MCQ
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C(x) = 400,000 + 120x + 0.003x²
dollars to manufacture x smartphones in an hour.
(a) Find the marginal cost function.
120 + 0.006x
Use it to estimate how fast the cost is increasing when x = 10,000.
$ 180
per smartphone
Compare this with the exact cost of producing the 10,001st smartphone.
per smartphone. The exact cost of producing the 10,001st smartphone is $ 180.006
The cost is increasing at a rate of $ 180
difference of $ 0.006
. Thus, there is a
(b) Find the average cost function C and the average cost to produce the first 10,000 smartphones.
400000
C(x) =
+ 120 + 0.003x
%D
C(10,000) = $ 190
%D
Transcribed Image Text:C(x) = 400,000 + 120x + 0.003x² dollars to manufacture x smartphones in an hour. (a) Find the marginal cost function. 120 + 0.006x Use it to estimate how fast the cost is increasing when x = 10,000. $ 180 per smartphone Compare this with the exact cost of producing the 10,001st smartphone. per smartphone. The exact cost of producing the 10,001st smartphone is $ 180.006 The cost is increasing at a rate of $ 180 difference of $ 0.006 . Thus, there is a (b) Find the average cost function C and the average cost to produce the first 10,000 smartphones. 400000 C(x) = + 120 + 0.003x %D C(10,000) = $ 190 %D
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