(D² + 6D + 7)(D3 – 5D² + 6D)y = %3D

Q: 3. (D3-2D2+D-2) y=0 4. (4D3+28D²+61D+37) y=0

A:

Q: (D³ – 3D + 2)y = -7 5.

A: Solve the following

Q: d) (D3 – 3D2 + 4D – 2)y = e* -

A:

Q: c2 c4-x² xe²y 2. dy dx 4-y

A:

Q: 4. (D2 - 5D + 4)y = 2x2 - 6x – 5 フェ

A:

Q: D² + 6D + 8)y = 12xe-4*

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Q: (D5+ D4-7D³ - 11D²8D-12)y = 0

A:

Q: 1. (D² -5D³)y = 4 2. (D³ – 5D* + 7D³ +D² -8D+4)y = 0

A:

Q: [D³ 6D² + 11 D - 6) y = tanx -

A: Sol:- Original Differential Equation can be re-written as :- y''' -6y'' +11y' -6y=tanxThe general…

Q: (4D3 + D)y = e2x

A:

Q: (e) y(ª) – 4y "= 5x² -e2* (g) y(“) +8y '= 4

A: The given differential equation is y(4)-4y''=5x2-e2x

Q: (D4 -1)y = 7x2

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Q: (D³ -3D* +4D³ -8D² +16),y = 0

A:

Q: (D5-11D4+19D³ + 115D² - 200D - 500)y = 0 Ans: y = C₂e-2x + C₂xe-2x + C₂e³x + ₂x³x + C5x²e³x

A:

Q: (D2 – 4D + 4)y = e3x

A: Given ODE is: (D2-4D+4)y=e3x

Q: 14. (D - 3D² - 6D + 8) y 3.x = xe

A:

Q: c. (D2 - 25)2 (D2-4D+ 13}3 y = 0 %3D

A: As per our guidelines we can answer only 1 question so kindly repost the remaining questions…

Q: 6. (D - 4D2 + 7D)y = 0 (D3

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Q: = B=( nds 2A – 38. Sean A %3D y B = Finds 2A 3B.

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Q: c. y = 4e (3x²-x) C.

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Q: (d) y" – 6y" + 11y' – 6y = e2" (5 – 4x – 3a²)

A: Given  A non homogeneous differential equation in question 2. D.

Q: (D³ – 3D + 2)y = -7 у" - 9y' %3D 27

A: (1).    The given differential equation is: D3-3D+2y=-7

Q: (D3−D2+4D−4)y=0 ; y(0)=2, y'(0)=7, y"(0)=-3

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Q: (D² - D - 2)y= 1-2x - 9e-2

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Q: 2. (D² + 4)y = 5e* - 4x

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Q: (D³ - 5D + 4)y = 0, when x = 0, y = -2, y' = 8, y" = 0

A: The given differential equation is: D3-5D+4y=0 when x=0, y=-2, y'=8, y''=0.

Q: (D² + 3D + 2)y = 12x²

A: The differential equation is given as (D2+3D+2)y=12x2 The corresponding homogeneous equation is…

Q: Find d2y/dx2 simplify in terms of x and y x2+y2=4

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Q: (D3+ 4D²+9D + 10) y= - 24e* when x=0, y=0, y'= - 4, y''=10

A:

Q: 2x + 글y=D2 %3D

A: Given,          The equation is 2x+12y=-2.

Q: d4y Q4\ b) Find : Y=3X³-4X²+7X+10 dx4

A: Given: Y=3x3-4x2+7x+10

Q: 2. (D3 + D2 - 2D)y = 0 %3D

A: Using method of linear differential equation.

Q: (D³ – 4D² + 4D)y = 0 (4D² – 6D + 1)y = 0 %3D

A:

Q: (D6 – 3D5 + 3Dª – D³)y = 12

A:

Q: 3. (D² – 3D + 2) y = 2x³ – 9x² + 6x

A:

Q: 4.) Q3- 5.) D8 6.) P39-

A: As per our guidelines we can solve first three sub part of question and rest can be reposted.…

Q: 10] D(xD2 - 2) is equal to (a) xD3 - 2D (b) (xD² – 2)D (c) xD -2 (d) xD³ + D2 - 2D

A:

Q: (D2 + 6D +9)y

A:

Q: - (D² – 1)y = 8xe*

A: Given that       (D2-1)y = 8xex Here we have to obtained the general solution.

Q: (20" + 6a²)dæ + 6x²) dæ Find (2,x7

A: ∫(2x7+6x2) dx

Q: 2) (D³ - 4D² + 4D - 16) y = 6 - 24x + 12x? - 16x³

A: Given: D3-4D2+4D-16y=6-24x+12x2-16x3

Q: (D⁴ + 6D² + 9)y = 0

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Q: (2D* + D3-4D2 - 10D - 4)y = 0

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Q: 4. (D² – 5D + 4)y = 4x

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Q: 3. (D5- D-2D3 + 2D2 +D – 1)y = 0

A: This is a differential equation problem

Q: 3. (D3 - 4D2 + 7D)y = - 11

A:

Q: 3. (D4 – 2D3 – 13D² + 38D – 24) = 0

A: As per bartleby guidelines we only give first question answers.

Q: (D4 + 6D3 + 9D2)y = 0

A:

Q: 3x2-3 and y(0) = 8, then y(1) = If dx 4. 12. 0. 8 6.

A: As a first step, let\'s rearrange the term. Please see the white board.