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d) an = 2an-1 - 3, ao = -1 e) an = (n + 1)an-1, ao = 2 f) an %3D %3D = 2nan-1, ao = 3 %3D

d) an = 2an-1 - 3, ao = -1 e) an = (n + 1)an-1, ao = 2 f) an %3D %3D = 2nan-1, ao = 3 %3D

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.6: Applications And The Perron-frobenius Theorem
Problem 56EQ
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Draw Highlight Erase and Matrices er c) an = 3(-1)" +2" – n + 2. d) an = 7.2" - n + 2. 16. Find the solution to each of these recurrence relations with the given initial conditions. Use an iterative approach such as that used in Example 10. as ly a) an = -an-1, ao = 5 k b) an = an-1+3, ao = 1 c) an = an-–1 – n, ao = 4 d) an e) an = (n + 1)an-1, ao = 2 f) an = 2na,-1, ao = 3 g) an = -an-1+n – 1, ao = 7 17. Find the solution to each of these recurrence relations and initial conditions. Use an iterative approach such as that used in Example 10. ne 2an-1 – 3, ao =-1 r- ne r- ch a) an = За,-1, ао = 2 = an-1 +2, ao = 3 c) an = an-1+n, ao = 1 d) an — аn-1+2n + 3, aо 3 4 = 2an-1 – 1, ao = 1 3an-1 + 1, ao = 1 b) an %3D e) а, — f) an g) an 3 nа,-1, ао 3D 5 2nan-1, ao = 1 18. A person deposits $1000 in an account that yields 9% interest compounded annually. h) an = a) Set up a recurrence relation for the amount in the ac-
Transcribed Image Text:Draw Highlight Erase and Matrices er c) an = 3(-1)" +2" – n + 2. d) an = 7.2" - n + 2. 16. Find the solution to each of these recurrence relations with the given initial conditions. Use an iterative approach such as that used in Example 10. as ly a) an = -an-1, ao = 5 k b) an = an-1+3, ao = 1 c) an = an-–1 – n, ao = 4 d) an e) an = (n + 1)an-1, ao = 2 f) an = 2na,-1, ao = 3 g) an = -an-1+n – 1, ao = 7 17. Find the solution to each of these recurrence relations and initial conditions. Use an iterative approach such as that used in Example 10. ne 2an-1 – 3, ao =-1 r- ne r- ch a) an = За,-1, ао = 2 = an-1 +2, ao = 3 c) an = an-1+n, ao = 1 d) an — аn-1+2n + 3, aо 3 4 = 2an-1 – 1, ao = 1 3an-1 + 1, ao = 1 b) an %3D e) а, — f) an g) an 3 nа,-1, ао 3D 5 2nan-1, ao = 1 18. A person deposits $1000 in an account that yields 9% interest compounded annually. h) an = a) Set up a recurrence relation for the amount in the ac-
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