d du 1) (sin-1u] dx %3D 1-u2 dx -1 du 리는 [cos-1 ul = dx V1-u2 dx d 1 du 3) = [tan-1 u] dx %3D 1+u2 dx -1 du 4)는 [cot-l u] = 5)을 [sec-l u] = %3D 1+u2 dx dx d 1 du %3D dx u vu2-1 dx -1 du 5)[ csc-1u] dx u vu2-1 dx

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 87E
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du
1) [sin-u]
dx
%3D
V1-u2 dx
2) [cos-1 u] =
-1
du
%3D
dx
V1-u2 dx
Coller
du
3)
dx
[tan-u]
%3D
1+u?
dx
d
[ cot-lu] =
5) - [sec-lu]
-1
du
4)
dx
%3D
1+u2
dx
1
du
%3D
dx
u vu2-1 dx
d
6)(csc-1 u]
-1
du
u vu2-1 dx
A OF 5
Transcribed Image Text:du 1) [sin-u] dx %3D V1-u2 dx 2) [cos-1 u] = -1 du %3D dx V1-u2 dx Coller du 3) dx [tan-u] %3D 1+u? dx d [ cot-lu] = 5) - [sec-lu] -1 du 4) dx %3D 1+u2 dx 1 du %3D dx u vu2-1 dx d 6)(csc-1 u] -1 du u vu2-1 dx A OF 5
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