d given by a = 2.82 - 0.003v², velocity in feet per second

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The driver of a car, which is initially at rest at the
top A of the grade, releases the brakes and coasts
down the grade with an acceleration in feet per
second squared given by a = 2.82 - 0.003v2,
where v is the velocity in feet per second.
Determine the velocity vg at the bottom B of the
grade.
755'
B
Transcribed Image Text:Question :) The driver of a car, which is initially at rest at the top A of the grade, releases the brakes and coasts down the grade with an acceleration in feet per second squared given by a = 2.82 - 0.003v2, where v is the velocity in feet per second. Determine the velocity vg at the bottom B of the grade. 755' B
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