(D3 + 30² -4)y=Do

Q: 3. (D3-2D2+D-2) y=0 4. (4D3+28D²+61D+37) y=0

A:

Q: -2c d10 (-12c³d7)(18c°d)

A:

Q: 2. f0x) =D(금x-푸)+3

A:

Q: (D3 + 4D² + 9D + 10)y = -24e* %3D

A: Let's find.

Q: c2 c4-x² xe²y 2. dy dx 4-y

A:

Q: 1. (D²-5D+6)y = 2e

A: This is a problem of differential equation.

Q: (D² + D2)y=e-²x + 3e²x

A:

Q: (4D4 - 4D3 - 3D2 - 2D + 1)y = 0

A: We have to solve the given equation.

Q: 1. (D³ - 3D²D + 3)y = 0

A: To Solve: (D3-3D2-D+3)y=0.

Q: (Dª + 3D³ – 6D² – 28D – 24)y = 0 -

A:

Q: D2 – 5D +6)y=3xex+2x2 , y(0)=0,y,(0)=1

A: Given differential equation is homogeneous ordinary differential equation. To solve this equation…

Q: d'y d³y - dx5 dx3 = 24.

A: Solution :-

Q: y= - x+2x +3

A:

Q: (D2 – 1)y = 2e-*(1+e-2*)-2, %3D

A:

Q: Xdy-ydメ-x2きdy2a

A:

Q: (D6 + 6D4 + 12D² + 8)y = 0 %3D

A: Given,…

Q: d²y +y D0 dx2

A:

Q: (4D3 + D)y = e2x

A:

Q: y = - x+2x +3

A: Given,            y=-x^2+2x+3

Q: (D² – 9D)(D² – 8D + 7)y = 0 |

A: We have to find the solutions of the given differential equations

Q: 3 -3x (0°+ 4D* - 30- 18)y= 24 x e

A:

Q: d2y/dx2, where y = 4x3/2

A: Given- y=4x32 To Find- d2ydx2 Identity Used- The power rule of derivative ddxxn=nxn-1

Q: [D³ – D)y = -2(1+x) + 4e* - 6e¬* + 96e3× %3D

A:

Q: -D12- 4.

A: there is only one variable to find the solution.

Q: 6. (D - 4D2 + 7D)y = 0 (D3

A:

Q: x° +2 y=- e3x +9

A: Given: As x→∞, y=x6+2e3x+9 To find: limx→∞x6+2e3x+9

Q: 3. (D5 –Dª – 2D³ +18D² –31D+15)y =0

A: Given differential equation is D5-D4-2D3+18D2-31D+15y = 0

Q: =D5 -3x+4y%3D8

A: y=5 -3x+4y=8

Q: y" + 14y' + 49y = -5 e-7x %3D

A:

Q: (D³ - 3D² - 6D + 8)y = xe

A:

Q: 3x² - y2 = 8 x2 + 3y2 16

A: we have to use the elimination method to solve the given equations.

Q: 5. (D4 + 2D3 + 10D²)y = 0

A:

Q: S- (x²a*)% 2 군

A: solution:- let x = a sec theta.

Q: y' +2y = -x8y5 will be transformed to the follo"

A: Given: - The Bernoulli's equation is, y'+3xy=-x8y5 To transformed: - The given Bernoulli's equation…

Q: Find d2y/dx2 simplify in terms of x and y x2+y2=4

A:

Q: Find x and y. C 2у — 4 - В 4x D 木 A

A: Given figure is parallelogram.

Q: 5a2 – 14.x + 6 d.x 13.) x3 -3x2

A:

Q: The Yp of (D²+D) y=20

A: Given (D2 + D) y = 20 To find yp(x)

Q: 6. (D² + 1)y =- 1 %3D 3

A:

Q: Vx2 – 4 d.x 3.

A: Please refer the attached image for complete solution.

Q: dy - 2ry = r'²

A:

Q: y= - x*+2x +3

A:

Q: ゾーゾY= t -8 り6)-2 ,S)。子 %3D

A:

Q: dx = 6x³ (3+ y²) 3/2

A:

Q: (D³ – 3D² + 4) y = 0

A:

Q: (2D* + D3-4D2 - 10D - 4)y = 0

A:

Q: x+y=D4 2. x-y%3D6

A: Given that, There are two equation following, x + y = 4…

Q: 3. (D3 - 4D2 + 7D)y = - 11

A:

Q: +2az+t D2 +(a+1)t%3D0

A: Matrix: 2x-y+2az+t=22x-y+(2a+1)z+(a+1)t=0-2x+y+(1-2a)z-2t=-6Here…