(D3 - 3D - 2)y =0; when x =0, y=0, y' = 9, y" = 0. 2x y = (-2 + 3r)e¯*+2e² B В y = (-1+ 2x)e2* + 2e ¬x © y = (- 2 + x)e¯*+2e* D y = (-1+ 2x)e-2+e2x

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
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Find the solution. (D3- 3D -2)y =0; when x =0, y=0, y' = 9, y" = 0. Answer is not sure please help
Find the solution.
(D3 - 3D - 2)y =0; when x =0, y=0, y' = 9, y" = 0.
y = (-2 + 3x)e¯+2e2x
В
y = (-1+ 2x)e2+2e ¬*
C y = (-2 + x)e¯*+2e*
D
y = (-1 + 2x)e-2*+ e2x
Transcribed Image Text:Find the solution. (D3 - 3D - 2)y =0; when x =0, y=0, y' = 9, y" = 0. y = (-2 + 3x)e¯+2e2x В y = (-1+ 2x)e2+2e ¬* C y = (-2 + x)e¯*+2e* D y = (-1 + 2x)e-2*+ e2x
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