Dave Fletcher was able to determine the activity times for constructing his laser scanning machine. Fletcher would like to determine ES, EF, LS, LF, and slack for each activity. The total project completion time and the critical path should also be determined. Here are the activity times: Time Immediate Predecessor(s) Activity (weeks) 5 7 9 8 Dave's earliest start (ES) and earliest finish (EF) are: Dave's latest start (LS) and latest finish (LF) are The slack times are: The activities on the critical path are The total project completion time for Dave weeks. ▼ Time Activity (weeks) A B C D 6 8 3 3 A A Activity A B C D E F G H Activity H G F E D C B A Activity A B C D E F G H LOI ES ☐ ☐ ☐ ☐☐ 0 6 8 LS 15 14 8 9 12 11 0 5 Slack | EF • 22 23 LF Immediate Predecessor(s) B C.E D.F

Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
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Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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Dave Fletcher was able to determine the activity times for constructing his laser scanning machine. Fletcher would like to determine ES, EF, LS, LF, and slack for each activity. The total project completion time and the critical path should also be determined. Here are the activity times:
Time
Activity (weeks)
Dave's earliest start (ES) and earliest finish (EF) are:
Dave's latest start (LS) and latest finish (LF) are:
The slack times are:
The activities on the critical path are
The total project completion time for Dave = weeks.
▼
Time
Immediate
Activity (weeks) Predecessor(s)
A
6
8
3
3
B
C
D
A
A
Activity
A
B
C
D
E
F
G
H
Activity
H
G
F
E
D
C
B
A
Activity
A
B
C
D
E
F
G
H
|
E
F
6
G
ES
□
0
H
8
T
П
LS
15
14
8
9
12
11
0
5
Slack
||
EF
6
13
22
23
5
7
9
8
LF
|
|
L
|
|
Immediate
Predecessor(s)
B
B
C, E
D,F
Transcribed Image Text:Dave Fletcher was able to determine the activity times for constructing his laser scanning machine. Fletcher would like to determine ES, EF, LS, LF, and slack for each activity. The total project completion time and the critical path should also be determined. Here are the activity times: Time Activity (weeks) Dave's earliest start (ES) and earliest finish (EF) are: Dave's latest start (LS) and latest finish (LF) are: The slack times are: The activities on the critical path are The total project completion time for Dave = weeks. ▼ Time Immediate Activity (weeks) Predecessor(s) A 6 8 3 3 B C D A A Activity A B C D E F G H Activity H G F E D C B A Activity A B C D E F G H | E F 6 G ES □ 0 H 8 T П LS 15 14 8 9 12 11 0 5 Slack || EF 6 13 22 23 5 7 9 8 LF | | L | | Immediate Predecessor(s) B B C, E D,F
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