D’(D² – 4)y = 3x+ 2e¬3* | y = 3x + 2e¬3x m° – 5 - 4m³ = 0 ® m' (m2 – 4) = 3x+2e-3* D (D² - 4) = 0 3 |

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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What is the auxiliary equation of the homogeneous linear DE associated with 

D’(D² – 4)y = 3x+ 2e¬3*
y = 3x + 2e¬3x
5
m°
– 4m³ = 0
© m' (m² – 4) = 3x+2e¬3*
D (D² – 4) = 0
Transcribed Image Text:D’(D² – 4)y = 3x+ 2e¬3* y = 3x + 2e¬3x 5 m° – 4m³ = 0 © m' (m² – 4) = 3x+2e¬3* D (D² – 4) = 0
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