) def 1 = = 5m | 3 2 m 233 + m² 10m3-232-5 (2m3,m2) - hld - N/W 2(2m3+m2) - 1 1 23+1 ㅋ 1 - 7m2 2(2m3+m2) 1 <③ 1 20+1 < 오늘

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 68E
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can somebody give me a step to step for the red circled steps for understanding what is happening?

thank you in advance!

an.
Them
Hence
en=
it
370
...
4
m²
et
3-6
using (ES) definition
1am - 21 = 11/1/21
using
+2
an =
et
m-10
(an) convergen to 2
1an-21 < E
(an)
5m
⇒ m² > {/1/2
4
ㅕ
choose m = [/]+
* ny m
(n =
=
n
2n4+n
et
mto
2
(1/1/2+2) = 2
11
convergen
;-)m
=
3
11
4
A2 LE
रह
n2
5 -
1
| Cm - 5/2 1 = // | 5n
2 + ½
(cm) converges to 5
(E-S) definition
my / E
+1
2
to 2
2n3 +n²
2/21
3
10 n²³-2n ² - 5 (2m² + m²)
2 (2n³+ m²)
1 =7m²
32.
2 (2m³ +m²)
23+1
7
5/2
ㅕ
• 1²₂-5/<
инече
Hence (Cn) converges to 5/2
1
<६
<2 E
20+1
2m) 27/1
ㅕ
7 m 2 - 2
4
[ 17/18 - 2] + 1
48
Transcribed Image Text:an. Them Hence en= it 370 ... 4 m² et 3-6 using (ES) definition 1am - 21 = 11/1/21 using +2 an = et m-10 (an) convergen to 2 1an-21 < E (an) 5m ⇒ m² > {/1/2 4 ㅕ choose m = [/]+ * ny m (n = = n 2n4+n et mto 2 (1/1/2+2) = 2 11 convergen ;-)m = 3 11 4 A2 LE रह n2 5 - 1 | Cm - 5/2 1 = // | 5n 2 + ½ (cm) converges to 5 (E-S) definition my / E +1 2 to 2 2n3 +n² 2/21 3 10 n²³-2n ² - 5 (2m² + m²) 2 (2n³+ m²) 1 =7m² 32. 2 (2m³ +m²) 23+1 7 5/2 ㅕ • 1²₂-5/< инече Hence (Cn) converges to 5/2 1 <६ <2 E 20+1 2m) 27/1 ㅕ 7 m 2 - 2 4 [ 17/18 - 2] + 1 48
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