Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns as a number the volume of a pyramid with a rectangular base. Sample output with inputs: 4.5 2.1 3.0Volume for 4.5 2.1 3.0 is: 9.45Relevant geometry equations: Volume = base area x height x 1/3 Base area = base length x base widthDefine a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns as a number the volume of a pyramid with a rectangular base. Sample output with inputs: 4.5 2.1 3.0Volume for 4.5 2.1 3.0 is: 9.45Relevant geometry equations: Volume = base area x height x 1/3 Base area = base length x base width

Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns as a number the volume of a pyramid with a rectangular base. Sample output with inputs: 4.5 2.1 3.0Volume for 4.5 2.1 3.0 is: 9.45Relevant geometry equations: Volume = base area x height x 1/3 Base area = base length x base widthDefine a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns as a number the volume of a pyramid with a rectangular base. Sample output with inputs: 4.5 2.1 3.0Volume for 4.5 2.1 3.0 is: 9.45Relevant geometry equations: Volume = base area x height x 1/3 Base area = base length x base width

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter5: Repetition Statements

Section5.5: A Closer Look: Loop Programming Techniques

Problem 12E: (Program) Write a program that tests the effectiveness of the rand() library function. Start by...

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Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation.Relevant geometry equations:Volume = base area x height x 1/3(Watch out for integer division).Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5, 2.1, 3.0 is: 9.45 def calc_base_area(base_length, base_width): return base_length * base_width ''' Your solution goes here ''' length = float(input())width = float(input())height = float(input())print('Volume for', length, width, height, "is:", calc_pyramid_volume(length, width, height))
Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation.Relevant geometry equations:Volume = base area x height x 1/3(Watch out for integer division).Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5, 2.1, 3.0 is: 9.45 python def calc_base_area(base_length, base_width): return base_length * base_width ''' Your solution goes here ''' length = float(input())width = float(input())height = float(input())print('Volume for', length, width, height, "is:", calc_pyramid_volume(length, width, height))
Define a function CalcPyramidVolume with double data type parameters baseLength, baseWidth, and pyramidHeight, that returns as a double the volume of a pyramid with a rectangular base. Relevant geometry equations:Volume = base area x height x 1/3Base area = base length x base width.(Watch out for integer division). 419894.2696446.qx3zqy7 #include <iostream>using namespace std; /* Your solution goes here */ int main() { double userLength; double userWidth; double userHeight; cin >> userLength; cin >> userWidth; cin >> userHeight; cout << "Volume: " << CalcPyramidVolume(userLength, userWidth, userHeight) << endl; return 0;}
Create a function that scales, for example, an analog input value (counts) to measured value. Mao. the function can, for example, have 5 inputs and 1 output. The 5 inputs are then: In_value, Inn_Min, Inn_Max, Ut_Min and Ut_Max. The function value is then a scaled value.Example: If the input value is from an analog input (counts) which should correspond to a temperature between -20 and + 300 degrees then Inn_Min = 0, Inn_Max = 32767 (WAGO analog in), Ut_Min = -20 and Ut_Max = 300. Test the function and reflect on why we can realize this as a function and not have to create a function block. use e!CockPIT
Define a function which takes one parameter N, and use loop(s) to control and output a pyramid pattern as follows: print a total of N rows, the number of asterisks in each row equals the row number (e.g. the 1st row has 1 asteroid, the Nth row has N asteroids). Note the pattern should be center aligned. E.g. when N is 5, you will print the following pattern * * * * * * * * * * * * * * *
Implement a C function, named triangle, that outputs Pascal’s triangle. In general, the Pascal’s triangle can be represented as: 0C0 1C1 1C0 2C2 2C1 2C0 3C3 3C2 3C1 3C0 4C4 4C3 4C2 4C1 4C0. . .where nCr represents how many ways there are to choose r from n, not counting duplicates. The formula used to calculate nCr can be written as:nCr = n!/r!(n −r)!where n! is the factorial of n. The function triangle:• is called by value where exactly one parameter (the number of rows of Pascal’s triangle)is passed to it.• returns void (i.e., no value).• prints out Pascal’s triangle to the standard output.• Employs two other functions, namely:– int choose(int n, int r);That chooses r from n– int factorial(int n);That calculates the factorial of n.Note: You are allowed — in fact, encouraged — to design and use any other functions as needed. Note:• The number of the rows is limited to integers between 0 and 13 inclusive.• If 0 is entered…
Write a function that makes the base conversion. It takes two integers n and b as input (n >= 0 andb > 1, both in base 10) and expresses n in base b. For example, the decimal expansion of 345 inbase 10 is 345 = 3 × 102 + 4 × 101 + 5 × 100.Sample input: n = 12, b =2. Sample output: 1100Explanation: (12)10 = (1100)2
Write a function print_shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N : Lather and rinse." num_cycles times, where N is the cycle number, followed by "Done.".Sample output with input: 1: Lather and rinse. 2: Lather and rinse. Done. So far, this is what I have and it works except that it doesnt do 2 lather and rinse outputs: def print_shampoo_instructions(num_cycles): if num_cycles < 1: print('Too few') elif num_cycles > 4: print('Too many') else: print(str(num_cycles - 1) + ': Lather and rinse.') num_cycles += 1 user_cycles = int(input())print_shampoo_instructions(user_cycles) user_cycles = int(input())print_shampoo_instructions(user_cycles)
A = 3 B = 6 C = 9 D= 7 mod10(X) is a function that returns the modulus of X after dividing it to 10. abs(X) is a function that returns the absolute value of X. Examples: mod10(6) = 6, mod10(16)=6, mod10(0) = 0, mod10(15)=5, mod10(41)+12 = 13 abs(4-8) = 4, abs(8-4)=4, abs(2-9) = 7, abs(8-1) = 7, abs(4-4)=0, abs(2-9)+8 = 15 Calculate the following: K1 = mod10(A+B) + 1= ……. K2 = abs(C-D) + 3 = ……. K3 = abs(D-2) + 1 = ……. K4 = mod10(A+B+C+D) + 1 = ……. K1 = mod((A+B), 10) + 1; K2 = abs(C-D) + 3; K3 = abs((D-2)) + 1; K4 = mod((A+B+C+D),10)+1;
Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base.Sample output with inputs: 4.5 2.1 3.0Volume for 4.5, 2.1, 3.0 is: 9.45 Relevant geometry equations:Volume = base area x height x 1/3Base area = base length x base width. ''' Your solution goes here ''' length = float(input())width = float(input())height = float(input())print('Volume for', length, width, height, "is:", calc_pyramid_volume(length, width, height))
Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base.Sample output with inputs: 4.5 2.1 3.0Volume for 4.5, 2.1, 3.0 is: 9.45 Relevant geometry equations:Volume = base area x height x 1/3Base area = base length x base width. ''' Your solution goes here ''' length = float(input())width = float(input())height = float(input())print('Volume for', length, width, height, "is:", calc_pyramid_volume(length, width, height)) python
(Python) Define a function calc_pyramid_volume() with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base. calc_pyramid_volume() calls the given calc_base_area() function in the calculation.Relevant geometry equations:Volume = base area x height x 1/3(Watch out for integer division).Sample output with inputs: 4.5 2.1 3.0Volume for 4.5, 2.1, 3.0 is: 9.45