Define T: P3 → P3 by T(p) = p(0) - p(1)t - p(1)t2 + p(0)t³. Find 7(p), where p = 1+t+t² + t³ and state if p is an eigenvector of T. OT(p)=1-t-t² +³ and p is an eigenvector of T OT(p)=4-t-t² + 4t³ and p is an eigenvector of T OT(p)=4-t-t² + 4t and p is not an eigenvector of T OT(p)=1-t-f + and p is not an eigenvector of T OT(p)=1-4t-4t² +³ and p is an eigenvector of T. OT(p)=1-4t-4f²+ and p is not an eigenvector of T

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.1: Eigenvalues And Eigenvectors
Problem 8E
icon
Related questions
Question
25
Define T: P3 → P3 by T(p) = p(0) - p(1)t - p(1)t2 + p(0)t³3. Find 7(p), where p = 1+t+t² + t³ and state if
p is an eigenvector of T
OT(p)=1-t-t² +³ and p is an eigenvector of T
OT(p)=4-t-t²
+4+³ and p is an eigenvector of T .
OT(p)=4-t-t²
+4t³ and p is not an eigenvector of T
OT(p)=1-t- + and p is not an eigenvector of T
OT(p)=1-4t-4t² +t³ and p is an eigenvector of T.
OT(p)=1-4t-4t²+
and p is not an eigenvector of T
Transcribed Image Text:Define T: P3 → P3 by T(p) = p(0) - p(1)t - p(1)t2 + p(0)t³3. Find 7(p), where p = 1+t+t² + t³ and state if p is an eigenvector of T OT(p)=1-t-t² +³ and p is an eigenvector of T OT(p)=4-t-t² +4+³ and p is an eigenvector of T . OT(p)=4-t-t² +4t³ and p is not an eigenvector of T OT(p)=1-t- + and p is not an eigenvector of T OT(p)=1-4t-4t² +t³ and p is an eigenvector of T. OT(p)=1-4t-4t²+ and p is not an eigenvector of T
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Recommended textbooks for you
Elementary Linear Algebra (MindTap Course List)
Elementary Linear Algebra (MindTap Course List)
Algebra
ISBN:
9781305658004
Author:
Ron Larson
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning