Definition: The AREA A of the region S that lies under the graph of the continuous function f is the limit of the sum of the areas of approximating rectangles A = lim Rn = lim [f(x1)Ax + f(xæ2)Ar+.+f(xn)Az] no0 no0 (a) Use the above definition to determine which of the following expressions represents the area under the graph of f(x) = x³ from x = 0 to x = 2. 64 25 TH00 TL i=l A. lim 1 В. lim 64 C. lim 64 D. lim n00 n6 i=1 (b) Evaluate the limit that is the correct answer to part (a). You may find the following formula helpful: n2(n + 1)²(2n² + 2n – 1) 15 + 25 + 35+..+n³ = %3D 12 Value of limit = LIWIWIWI

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.1: Inverse Functions
Problem 62E
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Definition: The AREA A of the region S that lies under the graph of the continuous function f is the limit of the sum of the areas of approximating
rectangles
A = lim Rn = lim [f(x1)Ax + f(xæ2)Ar+.+f(xn)Az]
n00
n00
(a) Use the above definition to determine which of the following expressions represents the area under the graph of f(x) = x³ from x = 0 to x = 2.
64
25
TH00 TL i=1
A. lim
1
В. lim
n+00 n6
64
C. lim
64
D. lim
n-00 n6
i=1
(b) Evaluate the limit that is the correct answer to part (a). You may find the following formula helpful:
15 + 25 + 35+.+n³ =
25
n2(n + 1)²(2n² + 2n – 1)
12
Value of limit =
Transcribed Image Text:Definition: The AREA A of the region S that lies under the graph of the continuous function f is the limit of the sum of the areas of approximating rectangles A = lim Rn = lim [f(x1)Ax + f(xæ2)Ar+.+f(xn)Az] n00 n00 (a) Use the above definition to determine which of the following expressions represents the area under the graph of f(x) = x³ from x = 0 to x = 2. 64 25 TH00 TL i=1 A. lim 1 В. lim n+00 n6 64 C. lim 64 D. lim n-00 n6 i=1 (b) Evaluate the limit that is the correct answer to part (a). You may find the following formula helpful: 15 + 25 + 35+.+n³ = 25 n2(n + 1)²(2n² + 2n – 1) 12 Value of limit =
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