Derive the canonical form of the given parabolic PDE (b) - 3u. +64.- 3u = cos(x).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 10RE
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Consider the 2nd order PDE
-3u+6xu-3u w=cos(x).
XX
ху
yy
Derive the canonical form of the given parabolic PDE
(b)
-3u +6u-3u= cos(x).
%3D
Transcribed Image Text:Consider the 2nd order PDE -3u+6xu-3u w=cos(x). XX ху yy Derive the canonical form of the given parabolic PDE (b) -3u +6u-3u= cos(x). %3D
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