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![Justify why the following instructions of 8086 are not correct. Correct them and specify the addressing
modes they come under after correction.
MOV AL, 2345H
DIV AX, BX
MOV DS, CS
JMP [BX][AX]
JMP 2000H:[2300H]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ca35359-b673-4475-b02c-0006c7cbe9cf%2F44404f03-f5fa-40ca-9f1e-23fafbaafc3e%2F2137mt_processed.jpeg&w=3840&q=75)
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- Explain how the 8086 microprocessor will code the following instruction into successive memory locations? Op-code for MOV is 100010. Use the Coding template for 8086 instructions which MOV data between registers or between register and a memory location. MOV AX, [C105]Please use x86 assembly for this question Write an assembly program that does the following:- Define the following value 0506-0307-0408-0102h in the .data segment using the 64-bit unsigned identifiernamed qVal.- You can subdivide the qVal value into 4 words – 0506, 0307, 0408, 0102- Extract these words from qVal using PTR operator.- Find the sum of the words. The sum should be D17h.- Store the result in any 16-bit register.Will upvote! Find the memory address of the next instruction executed by the microprocessor, when operated in the real mode, for the following CS:IP and 80286 register combinations: a. DS=2F2E & DX=9D64 b. CS=9F7A & IP=AB27 c. ES=DE21 & DI=D75F d. SS=FF5C & BP=92B8 e. DS=DC67 & CX=2FE8
- Q:Answer the following sentence with (True) or (False) and correct the false answer: 1. You can input data of size 16-bit through the fixed port. 2. In the maximum mode, the status signals S₁, S₂ and S3 are controlled by the bus controller. 3. HLDA is an output signal. 4. In 8086, when executing the instruction MOV AL, [SI+100D H] where SI-100AH, Ao=0 and BHE=1 5. When S, is 0, the TF is disabled.This question is on Computer Architecture. Translate the following arithmetic and logical expressions written in C programming language intoinstructions sequences written in MIPS Assembly language. You may assume that the values (orbase addresses) of the variables a, b, c, and d are in the general-purpose registers $s0, $s1,$s2, and $s3. 1. d[3] = a - b + c[7];2. c[5] = (a << 3) & (b >> 2);Here, <<, >>, and & indicate the bitwise left-shift, right-shift, and AND operations respectively.Suppose we have the instruction Load 0000. Given memory and register R1 contain thevalues below:R130Memory Address Content0000 40...0010 30...0020 78...0030 55...0040 77...0050 84 Assuming R1 is implied in the indexed addressing mode, determine the actual value loaded into the accumulator using the following addressing modes: a. Immediateb. Directc. Indirectd. Indexed
- Q1:Suppose the initial physical address of a segment register is given by 0E41:A02EH. Determine the physical address, base and final address of that segment register of 8086 microprocessorin 80886 microprocessor Suppose that. DS = 0200H, BX = 0300H, and DI-400H Determine the memory address accessed by each of the following instructions, assuming real mode operation: (1) MOV AL,[1234H] (2) MOV AX,[BX] (3) MOV [DI]ALIn 32-bit mode, aside from the stack pointer(ESP), what other register points to variables on the stack? Name at least four CPU status flags. Which flag is set when the result of an unsigned arithmetic operation is too large to fit into the destination? Which flag is set when the result of a signed arithmetic operation is either too large or too small to fit into the destination? (True/False): When a register operand size is 32 bits and the REX prefix is used, the R8D register is available for programs to use. Which flag is set when an arithmetic or logical operation generates a negative result? Which part of the CPU performs floating-point arithmetic? On a 32-bit processor, how many bits are contained in each floating-point data register? (True/False):The x86-64 instruction set is backward-compatible with the x86 instruction set. (True/False): In current 64-bit chip implementations, all 64 bits are used for addressing. (True/False):The Itanium…
- 333: E8B3 8B3: 0A12 A12: 2153 Since the contents of the relevant addresses are 333 in the basic computer given above, the initial value of the PC is 333; When fetching and executing an indirectly addressing ISZ instruction, write the contents of the following registers in hexadecimal (hex) format for the T5 time. AR ........... DR......... IR ........... PC ........... SC ...........With your knowledge in memory addressing mods and using the given opcodesSTCH = OX54Buffer = 1000 0101 0100(00) 1(x) 011 0000 0000 0000() What will be the target address?Please help with the following in regards to Nand2Tetris, and hack code, so hack assembly and hack vm. There can be more that one answer to a question if so please explain why. 1a. The A-instruction in the Hack computer performs a. direct addressing. b. immediate addressing. c. indirect addressing. d. bitwise addressing. 1b. Each memory address in the Hack computer references a. a single byte. b. a single word. c. multiple words. d. the D-register 1c. Given the following assembly code: (FOO) @FOO 0;JMP The purpose of the code is to : a. test of the value is = = 0 NO-OP b. jump to address 0 in RAM c. return a 0 to the calling code d. create an endless loop e. end the assembly language program 1d. Given a function called foo() that calls another external function bar() which in turn calls a second function called additup(). Indicate the VM line of code indicating the location in the program that control should be return to: a.@Foo.$bar. b. @Foo$bar$additup.ret.1 c.…