Describe the graph of the equation. r = -6i+ (1 – 1? )j + t k O It is a parabola in the plane z = -6, with vertex at (1, 0, -6), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 0, 1), opening to the 'right' (positive y) O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'right' (positive y) O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening up (positive z).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 26E
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Describe the graph of the equation.
r = -6i+ (1 – 1²)j + t k
O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'left' (negative y).
O It is a parabola in the plane x = -6, with vertex at (-6, 0, 1), opening to the 'right' (positive y).
O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'right' (positive y).
O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening to the 'left' (negative y).
O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening up (positive z).
Transcribed Image Text:Describe the graph of the equation. r = -6i+ (1 – 1²)j + t k O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 0, 1), opening to the 'right' (positive y). O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'right' (positive y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening up (positive z).
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