Determine all forces acting on member ABC of the linkage shown in Fig. 500 N B 300 mm 250 N 200 mm + 200 mm - 200 mm
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- The cable AB supports a uniformly distributed load of 12 lb/ft. Determine the angles A and B, and the cable tension at A.The linkage is made of two pin-connected A-36 steel members, each having a cross-sectional area of 1000 mm^2. Determine the magnitude of the force P needed to displace point A 0.425 mm downward.Find the value of P and the distance x so that the bar AB remains horizontal. Take the radius of the pulleys as 80 mm.
- Determine the internal normal force between lettered points on the cable and rod. Draw all necessary free-body diagrams.Draw the correct Free Body Diagram (FBD). Solve the Resultant Force at A. Given F1= 50lb and F2= 80lb.Determine the vertical displacement of joint C. Assume the supports at A and E are pins and joint C is pin connected. EI is constant. Use the method of virtual work.
- With F = 2000 lb, determine the force in the link CA. Express in pounds using three significant figures. Answer is not 71.43 or 1304Determine the normal tension of the cylinder piston rod (diameter 32mm). The clamping force of the pliers is 6000N. The dimensions of the structure are: x1 = 10 mm x2 = 120 mm y1 = 110 mmy2 = 798 mm Use the units [N, mm], ie the answer comes in MPa !!! Please enter a numeric value only !!Determine the resultant load on the most stressed bolt in the eccentrically loaded connections shown, using the elastic method.
- The ABD bracket is supported by a pin at A and the cable DE. Determine the internal forces immediately to the left of the load.Template: (On CD) F= 270 N; M=43.2 N.m; V = 90 NGiven bar having cross-sectional area of 700mm^2 is subjected to axial loads at the positions indicated.Draw up the diagrams of internal forces N,V and M of the following loads.